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Plot of logx/m against logp is a straight line inclined at an angle of 45 degree. When the pressure is 0.5 atm and Freundlich parameter, K is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 =0.6990)? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Plot of logx/m against logp is a straight line inclined at an angle of 45 degree. When the pressure is 0.5 atm and Freundlich parameter, K is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 =0.6990)? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Plot of logx/m against logp is a straight line inclined at an angle of 45 degree. When the pressure is 0.5 atm and Freundlich parameter, K is 10, the amount of solute adsorbed per gram of adsorbent will be (log5 =0.6990)?.

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