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The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:
  • a)
    15.16 JK–1mol–1
  • b)
    – 15.16 JK–1mol–1
  • c)
    – 5.05 JK–1mol–1
  • d)
    5.05 JK–1mol–1
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
The change in entropy when three moles of argon gas are heated at cons...
Calculation of Change in Entropy
To calculate the change in entropy, we can use the formula:

ΔS = nCv ln(T2/T1)

where ΔS is the change in entropy, n is the number of moles, Cv is the molar heat capacity at constant volume, T1 is the initial temperature, and T2 is the final temperature.

Given, n = 3 moles, Cv = 12.5 J K-1 mol-1 for monoatomic gases, T1 = 200 K, and T2 = 300 K.

ΔS = 3 × 12.5 J K-1 mol-1 × ln(300 K/200 K)
ΔS = 5.05 J K-1 mol-1

Therefore, the correct answer is option 'D' (5.05 JK-1mol-1).
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Community Answer
The change in entropy when three moles of argon gas are heated at cons...
You must be thinking that the answer should be A from the formula but options are given in J per Kelvin per mole so divide your answer with 3  i.e. 15.20/3=5.06 J per Kelvin per mole
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The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer?.
Solutions for The change in entropy when three moles of argon gas are heated at constant volume from 200 K to 300 K is:a)15.16 JK1mol1b) 15.16 JK1mol1c) 5.05 JK1mol1d)5.05 JK1mol1Correct answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry. Download more important topics, notes, lectures and mock test series for Chemistry Exam by signing up for free.
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