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If the ratio of the concentration of electrons to that of holes in a semiconductor is 7/5 and the ratio of the currents is 7/4, then what is the ratio of their drift velocities?
  • a)
    4/7
  • b)
    5/8
  • c)
    4/5
  • d)
    5/4
Correct answer is option 'C'. Can you explain this answer?
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Ratio of Electron Concentration to Hole Concentration
The given ratio of electron concentration to hole concentration is 7/5. This means that there are more electrons in the semiconductor than holes.

Ratio of Currents
The given ratio of currents is 7/4. This means that the current carried by the electrons is greater than the current carried by the holes.

Drift Velocity
The drift velocity is the average velocity that a charged particle (either an electron or a hole) attains due to the electric field in the semiconductor.

Formula
The ratio of drift velocities can be calculated using the formula:

v_d = μE

where v_d is the drift velocity, μ is the mobility of the charged particle, and E is the electric field in the semiconductor.

Analysis
Since the electric field is the same for both electrons and holes in the semiconductor, we can consider only the mobility of the charged particles.

The mobility of electrons and holes in a semiconductor depends on their effective masses, which are different. The mobility of the electrons is generally higher than that of the holes.

Since the current carried by the electrons is greater than that carried by the holes, it can be inferred that the mobility of the electrons is higher than that of the holes.

Therefore, the ratio of the drift velocities of electrons to holes is:

v_d(electron) / v_d(hole) = μ(electron) / μ(hole) > 1

The correct option is C, i.e., 4/5, which is the only option greater than 1.
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