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A block has been placed on an inclined plane. The slope angle θ of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is equal to  
  • a)
    sinθ
  • b)
    cos θ
  • c)
    g  
  • d)
    tan θ
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
A block has been placed on an inclined plane. The slope angle θ o...

At a constant speed means, acceleration is 0. Therefore, using formula
a = g( sinθ - ucosθ)
0 = g(sinθ - u cosθ)
ucosθ = sinθ
u = sinθ/cosθ
u= tanθ
Hence D is correct.
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Most Upvoted Answer
A block has been placed on an inclined plane. The slope angle θ o...
When the block slides down the plane with a constant speed, then the inclination of the plane is equal to angle of repose (q).
Coeff. of friction = tan of the angle of repose = tan q.
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Community Answer
A block has been placed on an inclined plane. The slope angle θ o...
Block is moving along the incline with constant velocity which means net force along the incline is zero...so mgsin¢=meu mgcos¢ Nd obtain the answer....
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A block has been placed on an inclined plane. The slope angle θ of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is equal to a)sinθb)cos θc)g d)tan θCorrect answer is option 'D'. Can you explain this answer? for Class 11 2025 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A block has been placed on an inclined plane. The slope angle θ of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is equal to a)sinθb)cos θc)g d)tan θCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Class 11 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A block has been placed on an inclined plane. The slope angle θ of the plane is such that the block slides down the plane at a constant speed. The coefficient of kinetic friction is equal to a)sinθb)cos θc)g d)tan θCorrect answer is option 'D'. Can you explain this answer?.
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