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 The A.M. between two numbers is 34 and their G.M. is 16.The numbers are
  • a)
    32 and 8
  • b)
    64 and 4
  • c)
    62 and 6
  • d)
    60 and 18
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
The A.M. between two numbers is 34 and their G.M. is 16.The numbers ar...
Let the numbers be x, y 
Then arithmatic mean = (x+y)/2 =34 
→x+y =68 
Also geometric mean =√(xy)=16 
oy xy=16^2=256 
Hence 
x(68−x)=256 
or x^2−68x+256=0 
(x−64)(x−4)=0 
Hence x=64 or x=4 
and y=4 or 64 
Larger number is 64

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Most Upvoted Answer
The A.M. between two numbers is 34 and their G.M. is 16.The numbers ar...
Let the numbers be x, y 
Then arithmatic mean = (x+y)/2 =34 
→x+y =68 
Also geometric mean =√(xy)=16 
oy xy=16^2=256 
Hence 
x(68−x)=256 
or x^2−68x+256=0 
(x−64)(x−4)=0 
Hence x=64 or x=4 
and y=4 or 64 
Larger number is 64
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Community Answer
The A.M. between two numbers is 34 and their G.M. is 16.The numbers ar...
Given Information:
- Arithmetic Mean (A.M.) between two numbers = 34
- Geometric Mean (G.M.) between two numbers = 16

Calculating the Numbers:
Let the numbers be x and y.

Arithmetic Mean (A.M.) formula:
A.M. = (x + y) / 2
34 = (x + y) / 2
x + y = 68 --- (1)

Geometric Mean (G.M.) formula:
G.M. = √(x * y)
16 = √(x * y)
x * y = 256 --- (2)

Solving Equations (1) and (2):
By solving equations (1) and (2), we find that the numbers are 64 and 4.
Therefore, the correct option is 64 and 4 (Option B).
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The A.M. between two numbers is 34 and their G.M. is 16.The numbers area)32 and 8b)64 and 4c)62 and 6d)60 and 18Correct answer is option 'B'. Can you explain this answer?
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