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In Young's double slit experiment, the wavelength of red light is 7800 Å and that of blue light is 5200 Å. The value of n for which nth bright band due to red light coincides with (n + 1)th bright band due to blue light, is
  • a)
    1
  • b)
    2
  • c)
    3
  • d)
    4
Correct answer is option 'B'. Can you explain this answer?
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In Young's double slit experiment, the wavelength of red light is ...
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In Young's double slit experiment, the wavelength of red light is ...
Given:
Wavelength of red light (λ_red) = 7800 Å
Wavelength of blue light (λ_blue) = 5200 Å

To find:
Value of n for which nth bright band due to red light coincides with (n + 1)th bright band due to blue light

Explanation:

1. Condition for bright fringes:
For bright fringes in Young's double-slit experiment, the path difference between the two waves should be an integer multiple of the wavelength. Mathematically, this condition can be expressed as:
mλ_red = (m + 1)λ_blue, where m is an integer

2. Solving for n:
Given that the nth bright band due to red light coincides with the (n + 1)th bright band due to blue light, we can set m = n:
nλ_red = (n + 1)λ_blue
Substitute the given values of λ_red and λ_blue:
n * 7800 = (n + 1) * 5200
Solve for n:
7800n = 5200n + 5200
2600n = 5200
n = 2

3. Answer:
Therefore, the value of n for which the nth bright band due to red light coincides with the (n + 1)th bright band due to blue light is 2. Hence, the correct answer is option B.
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In Young's double slit experiment, the wavelength of red light is ...
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In Young's double slit experiment, the wavelength of red light is 7800 Å and that of blue light is 5200 Å. The value of n for which nthbright band due to red light coincides with (n + 1)thbright band due to blue light, isa)1b)2c)3d)4Correct answer is option 'B'. Can you explain this answer?
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