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If A is a singular matrix, then A adj (A)
  • a)
    is an identity matrix
  • b)
    is a zero scalar
  • c)
    is a scalar matrix
  • d)
    is an orthogonal matrix
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
If A is a singular matrix, then A adj (A)a)is an identity matrixb)is a...
If A=0 (null and singular), then adj(A)=0 and hence adj(A) is singular too.
If A≠0 (nonnull and singular), then A contains a nonnull row, say the ith row a′i. It follows that
a′iadj(A)=0
which implies that the rows of adj(A) are linearly dependent, and hence adj(A) is singular.
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If A is a singular matrix, then A adj (A)a)is an identity matrixb)is a...
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If A is a singular matrix, then A adj (A)a)is an identity matrixb)is a...
Show that if A is singular , then adjA is also singular . I had been going to use the fact that if a matrix is singular, its determinant is 0, and the theorem that says that det(adj A) = [det(A)]^(n-1), but then realized that the theorem was only true if A was nonsingular
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If A is a singular matrix, then A adj (A)a)is an identity matrixb)is a zero scalarc)is a scalar matrixd)is an orthogonal matrixCorrect answer is option 'B'. Can you explain this answer?
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