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A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg?
Verified Answer
A motor car is moving with a velocity of 108 km per hour and it takes ...
U = 108 km/h => 108x5/18 => 6x5 => 30 m/s
v = 0m/s
t = 4sec
therefore , a = (v-u)/t
=>a = (0-30)/4
=> a = -30/4 => -7.5 m/s^2
force = mass x acceleration
force = 1000 kg x (-7.5) m/s^2
force = -7500 kg m/s^2
=> force = -7500 N
negative sign denotes opposing force
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Calculating the Force Exerted by the Brakes on the Motor Car
To calculate the force exerted by the brakes on the motor car, we need to consider the concept of deceleration and Newton's second law of motion.
1. Understanding the given information:
- Velocity of the motor car = 108 km/h = 108,000 m/3600 s = 30 m/s
- Time taken to stop after the brakes are applied = 4 seconds
- Mass of the motor car along with passengers = 1000 kg
2. Calculating the deceleration:
Deceleration is the rate at which the velocity of an object changes when it slows down. It can be calculated using the formula:
Deceleration (a) = Change in velocity (Δv) / Time taken (t)
The change in velocity can be calculated by subtracting the final velocity from the initial velocity:
Δv = Final velocity - Initial velocity
= 0 m/s - 30 m/s
= -30 m/s
Substituting the values into the formula, we get:
Deceleration (a) = -30 m/s / 4 s
= -7.5 m/s² (negative sign indicates deceleration)
3. Applying Newton's second law of motion:
Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:
Force (F) = Mass (m) x Acceleration (a)
Substituting the given values into the formula, we get:
Force (F) = 1000 kg x -7.5 m/s²
= -7500 N
4. Interpreting the result:
The negative sign indicates that the force exerted by the brakes is opposite to the direction of motion. This is because the force applied by the brakes is responsible for decelerating the car and bringing it to a stop.
Hence, the force exerted by the brakes on the motor car is 7500 Newtons in the opposite direction of motion.
To calculate the force exerted by the brakes on the motor car, we need to consider the concept of deceleration and Newton's second law of motion.
1. Understanding the given information:
- Velocity of the motor car = 108 km/h = 108,000 m/3600 s = 30 m/s
- Time taken to stop after the brakes are applied = 4 seconds
- Mass of the motor car along with passengers = 1000 kg
2. Calculating the deceleration:
Deceleration is the rate at which the velocity of an object changes when it slows down. It can be calculated using the formula:
Deceleration (a) = Change in velocity (Δv) / Time taken (t)
The change in velocity can be calculated by subtracting the final velocity from the initial velocity:
Δv = Final velocity - Initial velocity
= 0 m/s - 30 m/s
= -30 m/s
Substituting the values into the formula, we get:
Deceleration (a) = -30 m/s / 4 s
= -7.5 m/s² (negative sign indicates deceleration)
3. Applying Newton's second law of motion:
Newton's second law of motion states that the force acting on an object is equal to the mass of the object multiplied by its acceleration:
Force (F) = Mass (m) x Acceleration (a)
Substituting the given values into the formula, we get:
Force (F) = 1000 kg x -7.5 m/s²
= -7500 N
4. Interpreting the result:
The negative sign indicates that the force exerted by the brakes is opposite to the direction of motion. This is because the force applied by the brakes is responsible for decelerating the car and bringing it to a stop.
Hence, the force exerted by the brakes on the motor car is 7500 Newtons in the opposite direction of motion.
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A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg?
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A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg?.
A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A motor car is moving with a velocity of 108 km per hour and it takes 4 second to stop after the brakes are applied calculate the force exerted by the brakes on the motor car if its mass along with passenger is 1000 kg?.
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