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Equal weight of a solute are dissolved in equal weight of two solvents A and B formed very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering of vapour pressure for the solut ion A. If MA and MB are the mo lecular weights of so lvents A and B respectively, then:
  • a)
    MA = MB
  • b)
    MB = 2×MA
  • c)
    MA = 4MB
  • d)
    MA = 2MB
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Equal weight of a solute are dissolved in equal weight of two solvents...
Explanation:

Relative lowering of vapour pressure is given by the formula:

(Relative lowering of vapour pressure) = (Mole fraction of solute) x (Molecular weight of solvent) / (1000 x Density of solvent)

Let the weight of solute be w and weight of solvent A and B be WA and WB respectively.

So, for solvent A:

Mole fraction of solute = w / (MA x WA)
Relative lowering of vapour pressure for A = (w / (MA x WA)) x MA / (1000 x Density of A)

For solvent B:

Mole fraction of solute = w / (MB x WB)
Relative lowering of vapour pressure for B = 2 x (w / (MB x WB)) x MB / (1000 x Density of B)

It is given that both the solvents have equal weight of solute and the relative lowering of vapour pressure for solution B is twice that of solution A.

Therefore,

(w / (MA x WA)) x MA / (1000 x Density of A) = 2 x (w / (MB x WB)) x MB / (1000 x Density of B)

Simplifying this expression, we get:

MA / WB = 2 x MB / WA

Dividing both sides by MA, we get:

1 / (MA x WB) = 2 / (WA x MB)

1 / MA = 2 / MB

Hence, MB = 2 x MA. Therefore, option B is the correct answer.
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Equal weight of a solute are dissolved in equal weight of two solvents...
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Equal weight of a solute are dissolved in equal weight of two solvents A and B formed very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering of vapour pressure for the solut ion A. If MA and MB are the mo lecular weights of so lvents A and B respectively, then:a)MA = MBb)MB = 2MAc)MA = 4MBd)MA = 2MBCorrect answer is option 'B'. Can you explain this answer? for GRE 2025 is part of GRE preparation. The Question and answers have been prepared according to the GRE exam syllabus. Information about Equal weight of a solute are dissolved in equal weight of two solvents A and B formed very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering of vapour pressure for the solut ion A. If MA and MB are the mo lecular weights of so lvents A and B respectively, then:a)MA = MBb)MB = 2MAc)MA = 4MBd)MA = 2MBCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for GRE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Equal weight of a solute are dissolved in equal weight of two solvents A and B formed very dilute solution. The relative lowering of vapour pressure for the solution B has twice the relative lowering of vapour pressure for the solut ion A. If MA and MB are the mo lecular weights of so lvents A and B respectively, then:a)MA = MBb)MB = 2MAc)MA = 4MBd)MA = 2MBCorrect answer is option 'B'. Can you explain this answer?.
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