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An object of mass 100 kg is accelerated uniformly from a velocity of 5 M per second 28 M per second in 6 second calculate the initial and final momentum of the object also find the magnitude of the force exerted on the object?
Most Upvoted Answer
An object of mass 100 kg is accelerated uniformly from a velocity of 5...
M=100kg, u=5m/s, v=28m/s ,t=6second

Initial momentum =mu

=100×5=500kgm/s

Final momentum=mv

=100×28=2800kgm/s

Acceleration=v-u/t

=28-5/6=3.833

Force=ma

=100×3.833 =383.33N
Community Answer
An object of mass 100 kg is accelerated uniformly from a velocity of 5...
Initial and Final Momentum:

To calculate the initial and final momentum of the object, we can use the formula:

Momentum (p) = Mass (m) × Velocity (v)

Given:
Mass (m) = 100 kg
Initial velocity (u) = 5 m/s
Final velocity (v) = 28 m/s
Time (t) = 6 seconds

Initial momentum:
The initial momentum (p₁) can be calculated using the initial velocity (u):

p₁ = m × u
= 100 kg × 5 m/s
= 500 kg·m/s

Therefore, the initial momentum of the object is 500 kg·m/s.

Final momentum:
The final momentum (p₂) can be calculated using the final velocity (v):

p₂ = m × v
= 100 kg × 28 m/s
= 2800 kg·m/s

Therefore, the final momentum of the object is 2800 kg·m/s.

Magnitude of Force:

To find the magnitude of the force exerted on the object, we can use the equation:

Force (F) = Change in Momentum (Δp) / Time (t)

Given:
Change in momentum (Δp) = Final momentum (p₂) - Initial momentum (p₁)
= 2800 kg·m/s - 500 kg·m/s
= 2300 kg·m/s

Substituting the values into the equation:

F = Δp / t
= 2300 kg·m/s / 6 s
= 383.33 N

Therefore, the magnitude of the force exerted on the object is 383.33 N.

Summary:
- The initial momentum of the object is 500 kg·m/s.
- The final momentum of the object is 2800 kg·m/s.
- The magnitude of the force exerted on the object is 383.33 N.
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