An object of mass 100 kg is accelerated uniformly from a velocity of 5...
M=100kg, u=5m/s, v=28m/s ,t=6second
Initial momentum =mu
=100×5=500kgm/s
Final momentum=mv
=100×28=2800kgm/s
Acceleration=v-u/t
=28-5/6=3.833
Force=ma
=100×3.833 =383.33N
An object of mass 100 kg is accelerated uniformly from a velocity of 5...
Initial and Final Momentum:
To calculate the initial and final momentum of the object, we can use the formula:
Momentum (p) = Mass (m) × Velocity (v)
Given:
Mass (m) = 100 kg
Initial velocity (u) = 5 m/s
Final velocity (v) = 28 m/s
Time (t) = 6 seconds
Initial momentum:
The initial momentum (p₁) can be calculated using the initial velocity (u):
p₁ = m × u
= 100 kg × 5 m/s
= 500 kg·m/s
Therefore, the initial momentum of the object is 500 kg·m/s.
Final momentum:
The final momentum (p₂) can be calculated using the final velocity (v):
p₂ = m × v
= 100 kg × 28 m/s
= 2800 kg·m/s
Therefore, the final momentum of the object is 2800 kg·m/s.
Magnitude of Force:
To find the magnitude of the force exerted on the object, we can use the equation:
Force (F) = Change in Momentum (Δp) / Time (t)
Given:
Change in momentum (Δp) = Final momentum (p₂) - Initial momentum (p₁)
= 2800 kg·m/s - 500 kg·m/s
= 2300 kg·m/s
Substituting the values into the equation:
F = Δp / t
= 2300 kg·m/s / 6 s
= 383.33 N
Therefore, the magnitude of the force exerted on the object is 383.33 N.
Summary:
- The initial momentum of the object is 500 kg·m/s.
- The final momentum of the object is 2800 kg·m/s.
- The magnitude of the force exerted on the object is 383.33 N.
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