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Three circles A, B and C have a common center O. A is the inner circle, B middle circle and C is outer circle. The radius of the outer circle C, OP cuts the inner circle at X and middle circle at Y such that OX = XY = YP. The ratio of the area of the region between the inner and middle circles to the area of the region between the middle and outer circle is
  • a)
    1/3
  • b)
    2/5
  • c)
    3/5
  • d)
    1/5
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
Three circles A, B and C have a common center O. A is the inner circle...
let ox=1
ar. of A: (pie)
ar. of B: 4(pie)
ar. of C: 9(pie)

subtract to get middle areas
ratio = 3/5

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Most Upvoted Answer
Three circles A, B and C have a common center O. A is the inner circle...
Let's consider the radius of the inner circle A as r, the radius of the middle circle B as 2r, and the radius of the outer circle C as 3r.

1. Calculate the areas of the three circles:
- The area of circle A is πr^2.
- The area of circle B is π(2r)^2 = 4πr^2.
- The area of circle C is π(3r)^2 = 9πr^2.

2. Calculate the areas of the regions between the circles:
- The area between circles A and B is the difference between the area of circle B and the area of circle A: 4πr^2 - πr^2 = 3πr^2.
- The area between circles B and C is the difference between the area of circle C and the area of circle B: 9πr^2 - 4πr^2 = 5πr^2.

3. Calculate the areas of the regions defined by the tangents:
- The area of the triangle OXP is (1/2)(OX)(XP) = (1/2)(r)(r) = (1/2)r^2.
- The area of the triangle OYP is (1/2)(OY)(YP) = (1/2)(2r)(r) = r^2.
- The area of the triangle PXY is (1/2)(XY)(PY) = (1/2)(r)(r) = (1/2)r^2.

4. Calculate the ratio of the area between the inner and middle circles to the area between the middle and outer circle:
- The area between the inner and middle circles is 3πr^2.
- The area between the middle and outer circles is 5πr^2.
- The ratio of these two areas is (3πr^2)/(5πr^2) = 3/5.

Therefore, the correct answer is option 'C': 3/5.
Free Test
Community Answer
Three circles A, B and C have a common center O. A is the inner circle...
let the radius of the A circle be x..
so.. radii of B and C are 2x and 3x respectively.
Area of the first given part will be pi(2x)^2 - pi(x)^2 = 3pi x^2                   ---1
Area of the second given part will be pi(3x)^2 - pi(2x)^2 = 5pi x^2           ---2

dividing 1 and 2... we get 3/5

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Three circles A, B and C have a common center O. A is the inner circle, B middle circle and C is outer circle. The radius of the outer circle C, OP cuts the inner circle at X and middle circle at Y such that OX = XY = YP. The ratio of the area of the region between the inner and middle circles to the area of the region between the middle and outer circle isa)1/3b)2/5c)3/5d)1/5Correct answer is option 'C'. Can you explain this answer?
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