Class 9 Exam  >  Class 9 Questions  >  A body of mass 20 kg, slows down from 5 ms-1t... Start Learning for Free
A body of mass 20 kg, slows down from 5 ms-1 to 2 ms-1 by a retarding force. The work done by the force is:
  • a)
    –50J
  • b)
    –200J
  • c)
    –300J
  • d)
    –210J
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding fo...
W=kinetic energy possessed. .
=[(1/2) (m) (v^2)] - [(1/2 ) (m) (u^2)]...
=(1/2) (m) [(v^2)-(u^2)]...
=(1/2) (20) [(2×2)-(5×5)]..
=(10) (-21)...
=(-210)J . ...
Free Test
Community Answer
A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding fo...
180 J

To calculate the work done by the force, we can use the formula:

Work = force x distance x cos(theta)

where force is the retarding force, distance is the distance traveled while the force is acting, and theta is the angle between the force and the direction of motion.

In this case, we know the initial and final velocities of the body, so we can calculate the change in velocity:

Change in velocity = final velocity - initial velocity
= 2 ms^-1 - 5 ms^-1
= -3 ms^-1

Since the body is slowing down, the direction of the force is opposite to the direction of motion, so theta = 180 degrees. We also know the mass of the body, so we can calculate the force using Newton's second law:

force = mass x acceleration

The acceleration is given by:

acceleration = (final velocity - initial velocity) / time taken

We don't know the time taken, but we can use the fact that the body is slowing down to write:

time taken = distance / average velocity

where distance is the distance traveled while the force is acting, and average velocity is the average of the initial and final velocities:

average velocity = (final velocity + initial velocity) / 2
= (2 ms^-1 + 5 ms^-1) / 2
= 3.5 ms^-1

We can solve for distance using the formula:

distance = average velocity x time taken

Substituting the expressions for time taken and average velocity, we get:

distance = (final velocity - initial velocity) x mass / acceleration
= (-3 ms^-1) x (20 kg) / ((2 ms^-1 - 5 ms^-1) / time taken)
= 60 m

Now we can calculate the force:

force = mass x acceleration
= (20 kg) x ((2 ms^-1 - 5 ms^-1) / time taken)
= (20 kg) x (-3 ms^-2 / (60 m / (3 ms^-1)))
= -30 N

The negative sign indicates that the force is in the opposite direction to the motion of the body.

Finally, we can calculate the work done by the force:

Work = force x distance x cos(theta)
= (-30 N) x (60 m) x cos(180 degrees)
= -1800 J

The negative sign indicates that the work done by the force is negative, which means that the force is doing work against the motion of the body. To get the magnitude of the work done, we can take the absolute value:

|Work| = 1800 J

Therefore, the work done by the retarding force is 180 J.
Explore Courses for Class 9 exam

Top Courses for Class 9

Question Description
A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? for Class 9 2025 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? covers all topics & solutions for Class 9 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer?.
Solutions for A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for Class 9. Download more important topics, notes, lectures and mock test series for Class 9 Exam by signing up for free.
Here you can find the meaning of A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer?, a detailed solution for A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? has been provided alongside types of A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice A body of mass 20 kg, slows down from 5 ms-1to 2 ms-1by a retarding force. The work done by the force is:a)–50Jb)–200Jc)–300Jd)–210JCorrect answer is option 'B'. Can you explain this answer? tests, examples and also practice Class 9 tests.
Explore Courses for Class 9 exam

Top Courses for Class 9

Explore Courses
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev