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A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s?
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A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and...
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A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and...
Given Parameters:
- Mass of the golf ball, m = 4.8 * 10^–2 kg
- Initial speed of the golf ball, u = 0 (as it is stationary)
- Final speed of the golf ball, v = 95 m/s
- Average force exerted, F = 7800 N
- Time of contact, t = ?
Using Newton's Second Law:
The force exerted on the golf ball can be related to its change in momentum using Newton's second law:
F = (m * (v - u)) / t
Calculating the time of contact:
Substitute the given values into the equation:
7800 = (4.8 * 10^–2 * 95) / t
7800 = 4.56 / t
t = 4.56 / 7800
t ≈ 5.8 * 10^–4 s
Therefore, the ball and club are in contact for approximately 5.8 * 10^–4 seconds.
Thus, the correct answer is A) 5.8 * 10^–4 s.
- Mass of the golf ball, m = 4.8 * 10^–2 kg
- Initial speed of the golf ball, u = 0 (as it is stationary)
- Final speed of the golf ball, v = 95 m/s
- Average force exerted, F = 7800 N
- Time of contact, t = ?
Using Newton's Second Law:
The force exerted on the golf ball can be related to its change in momentum using Newton's second law:
F = (m * (v - u)) / t
Calculating the time of contact:
Substitute the given values into the equation:
7800 = (4.8 * 10^–2 * 95) / t
7800 = 4.56 / t
t = 4.56 / 7800
t ≈ 5.8 * 10^–4 s
Therefore, the ball and club are in contact for approximately 5.8 * 10^–4 seconds.
Thus, the correct answer is A) 5.8 * 10^–4 s.
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A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s?
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A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s?.
A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s? for Class 9 2024 is part of Class 9 preparation. The Question and answers have been prepared according to the Class 9 exam syllabus. Information about A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s? covers all topics & solutions for Class 9 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A golf club strikes a stationary golf ball of mass 4.8 * 10^–2 kg and the ball leaves the club with a speed of 95 ms–1. If the average force exerted on the ball is 7800 N, how long are the ball andclub in contact? A 5.8 * 10^–4s B 1.2 * 10^–2s C 0.51 s D 0.58 s?.
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