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A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).
Correct answer is between '1.42,1.46'. Can you explain this answer?
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A fault surface in an outcrop has slickenside lineation whose pitch is...
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A fault surface in an outcrop has slickenside lineation whose pitch is...
Understanding Fault Mechanics
When analyzing a fault surface with slickenside lineation, the pitch and horizontal slip are essential for determining the net slip.
Key Concepts
- Pitch: The angle of lineation compared to a horizontal plane. A pitch of 30 degrees indicates the inclination of the fault slip vector.
- Horizontal Slip: This is the measured displacement along the fault, which is 1.25 m in this scenario.
Calculating Net Slip
To find the net slip (S), we can use the relationship between horizontal slip (H) and the pitch (θ):
- Formula:
S = H / cos(θ)
Where:
- H = horizontal slip (1.25 m)
- θ = pitch (30 degrees)
Calculating Cosine of Pitch
- The cosine of 30 degrees is approximately 0.866.
Plugging in the Values
- S = 1.25 m / 0.866 ≈ 1.442 m
This value rounds to 1.44 m.
Final Net Slip Calculation
Thus, the net slip on the fault is approximately:
- Net Slip: 1.44 m
This value falls between the specified range of 1.42 m and 1.46 m, confirming the accuracy of the calculation.
Conclusion
Understanding the relationship between pitch and horizontal slip is crucial for fault analysis. The net slip derived reflects the true movement along the fault plane.
When analyzing a fault surface with slickenside lineation, the pitch and horizontal slip are essential for determining the net slip.
Key Concepts
- Pitch: The angle of lineation compared to a horizontal plane. A pitch of 30 degrees indicates the inclination of the fault slip vector.
- Horizontal Slip: This is the measured displacement along the fault, which is 1.25 m in this scenario.
Calculating Net Slip
To find the net slip (S), we can use the relationship between horizontal slip (H) and the pitch (θ):
- Formula:
S = H / cos(θ)
Where:
- H = horizontal slip (1.25 m)
- θ = pitch (30 degrees)
Calculating Cosine of Pitch
- The cosine of 30 degrees is approximately 0.866.
Plugging in the Values
- S = 1.25 m / 0.866 ≈ 1.442 m
This value rounds to 1.44 m.
Final Net Slip Calculation
Thus, the net slip on the fault is approximately:
- Net Slip: 1.44 m
This value falls between the specified range of 1.42 m and 1.46 m, confirming the accuracy of the calculation.
Conclusion
Understanding the relationship between pitch and horizontal slip is crucial for fault analysis. The net slip derived reflects the true movement along the fault plane.
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A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? for IIT JAM 2025 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? covers all topics & solutions for IIT JAM 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer?.
A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? for IIT JAM 2025 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? covers all topics & solutions for IIT JAM 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer?.
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A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer?, a detailed solution for A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? has been provided alongside types of A fault surface in an outcrop has slickenside lineation whose pitch is 30°. The horizontal slip on the fault is 1.25 m, as determined from displaced vein. The net slip on the fault is ____ meter (give answer in two decimal places).Correct answer is between '1.42,1.46'. Can you explain this answer? theory, EduRev gives you an
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