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A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).
Correct answer is between '0.21,0.23'. Can you explain this answer?
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A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has...
Given data:
- Diameter of the ore body = 20 m
- Length of the ore body = 200 m
- Metal content = 5%
- Density of the ore body = 3500 kg/m3
Calculating the volume of the ore body:
The ore body is in the shape of a cylinder, so we can calculate its volume using the formula:
Volume = π * (radius)2 * length
Given that the diameter is 20 m, we can calculate the radius as:
radius = diameter / 2 = 20 / 2 = 10 m
Substituting the values into the formula:
Volume = π * (10)2 * 200
= 3.14 * 100 * 200
= 62800 m3
Calculating the mass of the ore body:
The mass of the ore body can be calculated using the formula:
Mass = Volume * Density
Substituting the values:
Mass = 62800 * 3500
= 219800000 kg
Converting mass to million tons:
To convert the mass from kilograms to million tons, we divide the mass by 1 million:
Mass_in_million_tons = Mass / (1 million)
= 219800000 / 1000000
= 219.8 million tons
Final answer:
Therefore, the reserve of the ore body is 219.8 million tons, which can be rounded to 2 decimal places as 0.22 million tons.
- Diameter of the ore body = 20 m
- Length of the ore body = 200 m
- Metal content = 5%
- Density of the ore body = 3500 kg/m3
Calculating the volume of the ore body:
The ore body is in the shape of a cylinder, so we can calculate its volume using the formula:
Volume = π * (radius)2 * length
Given that the diameter is 20 m, we can calculate the radius as:
radius = diameter / 2 = 20 / 2 = 10 m
Substituting the values into the formula:
Volume = π * (10)2 * 200
= 3.14 * 100 * 200
= 62800 m3
Calculating the mass of the ore body:
The mass of the ore body can be calculated using the formula:
Mass = Volume * Density
Substituting the values:
Mass = 62800 * 3500
= 219800000 kg
Converting mass to million tons:
To convert the mass from kilograms to million tons, we divide the mass by 1 million:
Mass_in_million_tons = Mass / (1 million)
= 219800000 / 1000000
= 219.8 million tons
Final answer:
Therefore, the reserve of the ore body is 219.8 million tons, which can be rounded to 2 decimal places as 0.22 million tons.
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A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer?
Question Description
A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer?.
A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer?.
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