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A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).
    Correct answer is between '0.21,0.23'. Can you explain this answer?
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    A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has...
    Given data:
    - Diameter of the ore body = 20 m
    - Length of the ore body = 200 m
    - Metal content = 5%
    - Density of the ore body = 3500 kg/m3

    Calculating the volume of the ore body:
    The ore body is in the shape of a cylinder, so we can calculate its volume using the formula:

    Volume = π * (radius)2 * length

    Given that the diameter is 20 m, we can calculate the radius as:

    radius = diameter / 2 = 20 / 2 = 10 m

    Substituting the values into the formula:

    Volume = π * (10)2 * 200
    = 3.14 * 100 * 200
    = 62800 m3

    Calculating the mass of the ore body:
    The mass of the ore body can be calculated using the formula:

    Mass = Volume * Density

    Substituting the values:

    Mass = 62800 * 3500
    = 219800000 kg

    Converting mass to million tons:
    To convert the mass from kilograms to million tons, we divide the mass by 1 million:

    Mass_in_million_tons = Mass / (1 million)
    = 219800000 / 1000000
    = 219.8 million tons

    Final answer:
    Therefore, the reserve of the ore body is 219.8 million tons, which can be rounded to 2 decimal places as 0.22 million tons.
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    A horizontal cylindrical ore body (diameter = 20m, length = 200 m) has 5% metal content and density of 3500 kg/m3. The reserve of the ore body is ____ million ton(s) (give answer in two decimal places).Correct answer is between '0.21,0.23'. Can you explain this answer?
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