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The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadro’s number = 6 × 1023.
- a)224
- b)9
- c)140
- d)28
Correct answer is option 'D'. Can you explain this answer?
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The number of water molecules present in a 300 residue soluble protein...
To solve this problem, we need to calculate the volume of the protein and the volume of water present in it.
1. Volume of the protein:
Given that the diameter of the protein is 2 nm, we can calculate the radius as 1 nm (since radius = diameter/2). Using the formula for the volume of a sphere (V = 4/3 * π * r^3), we can calculate the volume of the protein.
V_protein = 4/3 * π * (1 nm)^3
2. Volume of water:
We are given that the protein has 20% (V/V) water. This means that 20% of the total volume of the protein is occupied by water. We can calculate the volume of water using this percentage.
V_water = 20% * V_protein
3. Number of water molecules:
To calculate the number of water molecules, we need to know the density of water and the molar mass of water. Given that the density of water is 1000 kg/m^3 and Avogadro's number is 6 * 10^23, we can calculate the molar mass of water using its chemical formula (H2O) and the atomic masses of hydrogen and oxygen.
Molar mass of water = (2 * atomic mass of hydrogen) + atomic mass of oxygen
Now, we can use the formula to calculate the number of water molecules:
Number of water molecules = (V_water * density of water) / molar mass of water
4. Calculation:
Let's plug in the values and calculate the number of water molecules:
V_protein = 4/3 * π * (1 nm)^3 = 4/3 * 3.14 * (1 nm)^3
V_water = 20% * V_protein
Number of water molecules = (V_water * density of water) / molar mass of water
Substituting the given values:
V_protein = 4/3 * 3.14 * (1 nm)^3 = 4/3 * 3.14 * (10^-9 m)^3
V_water = 20% * V_protein
Number of water molecules = (V_water * density of water) / molar mass of water
After calculating these values, we find that the number of water molecules is approximately 28. Therefore, the correct answer is option D.
1. Volume of the protein:
Given that the diameter of the protein is 2 nm, we can calculate the radius as 1 nm (since radius = diameter/2). Using the formula for the volume of a sphere (V = 4/3 * π * r^3), we can calculate the volume of the protein.
V_protein = 4/3 * π * (1 nm)^3
2. Volume of water:
We are given that the protein has 20% (V/V) water. This means that 20% of the total volume of the protein is occupied by water. We can calculate the volume of water using this percentage.
V_water = 20% * V_protein
3. Number of water molecules:
To calculate the number of water molecules, we need to know the density of water and the molar mass of water. Given that the density of water is 1000 kg/m^3 and Avogadro's number is 6 * 10^23, we can calculate the molar mass of water using its chemical formula (H2O) and the atomic masses of hydrogen and oxygen.
Molar mass of water = (2 * atomic mass of hydrogen) + atomic mass of oxygen
Now, we can use the formula to calculate the number of water molecules:
Number of water molecules = (V_water * density of water) / molar mass of water
4. Calculation:
Let's plug in the values and calculate the number of water molecules:
V_protein = 4/3 * π * (1 nm)^3 = 4/3 * 3.14 * (1 nm)^3
V_water = 20% * V_protein
Number of water molecules = (V_water * density of water) / molar mass of water
Substituting the given values:
V_protein = 4/3 * 3.14 * (1 nm)^3 = 4/3 * 3.14 * (10^-9 m)^3
V_water = 20% * V_protein
Number of water molecules = (V_water * density of water) / molar mass of water
After calculating these values, we find that the number of water molecules is approximately 28. Therefore, the correct answer is option D.
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The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer?
Question Description
The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer?.
The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer? for IIT JAM 2024 is part of IIT JAM preparation. The Question and answers have been prepared according to the IIT JAM exam syllabus. Information about The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for IIT JAM 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of water molecules present in a 300 residue soluble protein of spherical shape (diameter = 2 nm) having 20% (V/V) water is closed to Assume: density of water = 1000 kg/m3, Avogadros number = 6 1023.a)224b)9c)140d)28Correct answer is option 'D'. Can you explain this answer?.
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