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The vibrational frequency of a homonuclear diatomic molecule is v. The temperature at which the population of the first excited state will be half that of the ground state is given by.

  • a)
    hv . ln2 / kB

  • b)
    hv /(ln2 . kB)

  • c)
    ln2 /( hv . kB)

  • d)
    hv . log 2 / kB

Correct answer is option 'B'. Can you explain this answer?
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The vibrational frequency of a homonuclear diatomic molecule is v. The...

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The vibrational frequency of a homonuclear diatomic molecule is v. The...
Solution:

The energy of a homonuclear diatomic molecule is given by:

E(v) = (v + 1/2) hν

Where, v is the vibrational quantum number and h is the Planck's constant.

At a given temperature T, the population of a given vibrational level i is given by:

Ni/N0 = (gi/g0) exp(-Ei/kBT)

Where, gi and g0 are the degeneracies of the excited and ground states respectively, Ei is the energy of the excited state, and kB is the Boltzmann constant.

To find the temperature at which the population of the first excited state will be half that of the ground state, we need to solve the following equation:

N1/N0 = 1/2

(g1/g0) exp(-E1/kBT) = 1/2

Taking the natural logarithm of both sides, we get:

ln(g1/g0) - E1/kBT = ln(1/2)

ln(g1/g0) + E1/kB(T1/2) = ln(g1/g0) + E1/kBT

E1/kB(T1/2) = ln(2)

T1/2 = (ln2/kB) (E1/h)

Substituting the energy of the first excited state, E1 = 2hν, we get:

T1/2 = hv/(ln2.kB)

Therefore, the correct answer is option B.
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The vibrational frequency of a homonuclear diatomic molecule is v. The...
According to Boltzmann's population formula
N/n=exp(-E/kT)
As per question N=n/2 so
0.5=exp(-E/kT)
taking ln both side
ln(0.5)= -E/kT
ln(2)=hv/kT
so T=hv/(ln2.k)
where N=population in excited state
n=population in ground state
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The vibrational frequency of a homonuclear diatomic molecule is v. The temperature at which the population of the first excited state will be half that of the ground state is given by.a)hv .ln2 / kBb)hv /(ln2 .kB)c)ln2 /( hv .kB)d)hv .log 2 / kBCorrect answer is option 'B'. Can you explain this answer?
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