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a car is travelling with a velocity of 72 km h .if brakes are applied produce uniform retardation of 10 m s .calculate the time taken to stop.
Verified Answer
a car is travelling with a velocity of 72 km h .if brakes are applied ...
Initial velocity (u) = 72 km/h = 20 m/s
Final velocity (v) = 0
Acceleration (a) = - 10 m/s^2
Time taken to stop (t) = ?

We know,

v - u = at
0 - 20 = -10 x t
-20 = -10t
-20/-10 = t

t = 2 s

Time taken to stop = 2 seconds.
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Most Upvoted Answer
a car is travelling with a velocity of 72 km h .if brakes are applied ...
Given data:
- Velocity of the car, v = 72 km/h
- Retardation, a = 10 m/s²

To calculate:
- Time taken to stop the car

Conversion of units:
- We need to convert the velocity from km/h to m/s to match the unit of acceleration.
- 1 km/h = 1000 m/3600 s = 5/18 m/s
- Therefore, the velocity of the car in m/s is:
v = 72 km/h × (5/18 m/s) = 20 m/s

Using the equation of motion:
- We can use the equation of motion to find the time taken to stop the car:
v = u + at
Where,
v is the final velocity (0 m/s as the car stops),
u is the initial velocity (20 m/s),
a is the acceleration (retardation of 10 m/s²),
t is the time.

Substituting the values:
0 = 20 m/s + (-10 m/s²) × t

Simplifying the equation:
- Multiplying the acceleration by time:
0 = 20 m/s - 10 m/s² × t
10 m/s² × t = 20 m/s

- Dividing both sides by 10 m/s²:
t = 20 m/s / 10 m/s²
t = 2 s

Therefore, the car takes 2 seconds to stop.
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a car is travelling with a velocity of 72 km h .if brakes are applied produce uniform retardation of 10 m s .calculate the time taken to stop.
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