Introduction:
The kinetic energy of a satellite in its orbit around the Earth is given by the equation E = (1/2)mv^2, where E is the kinetic energy, m is the mass of the satellite, and v is its velocity. To escape the gravitational pull of the Earth, the satellite needs to have enough kinetic energy to overcome the gravitational potential energy.

Escape Velocity:
The escape velocity is the minimum velocity required for an object to escape the gravitational pull of a massive body, such as the Earth. It is given by the equation ve = sqrt(2GM/R), where ve is the escape velocity, G is the gravitational constant, M is the mass of the Earth, and R is the distance between the center of the Earth and the satellite.

Analysis:
To calculate the kinetic energy required for the satellite to escape the Earth's gravitational pull, we need to compare the kinetic energy in its orbit (E) with the kinetic energy required for escape (Ee).

Calculation:
1. The kinetic energy in the satellite's orbit is given by E = (1/2)mv^2.
2. The escape velocity is given by ve = sqrt(2GM/R).
3. The kinetic energy required for escape is given by Ee = (1/2)mve^2.

Solution:
To find the kinetic energy required for escape, we need to calculate the escape velocity and substitute it into the equation for kinetic energy.

1. The kinetic energy in the satellite's orbit is E = (1/2)mv^2.
2. The escape velocity is ve = sqrt(2GM/R).
3. The kinetic energy required for escape is Ee = (1/2)mve^2.

Substituting the value of ve into the equation for Ee, we get:
Ee = (1/2)m(sqrt(2GM/R))^2
= (1/2)m(2GM/R)
= GMm/R

Therefore, the kinetic energy required for escape is GMm/R.

Conclusion:
The kinetic energy required for the satellite to escape the gravitational pull of the Earth is GMm/R. Comparing this with the kinetic energy in the satellite's orbit (E), we can see that the kinetic energy required for escape is 2E. Therefore, the correct answer is (b) 2E.