All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  In the gaseous equilibriumthe formation ofwil... Start Learning for Free
In the gaseous equilibrium

the formation of  will be favored by
  • a)
    High pressure and low temperature
  • b)
    High temperature and low pressure
  • c)
    Low temperature and low pressure
  • d)
    High temperature and high pressure
Correct answer is option 'D'. Can you explain this answer?
Clear all your JEE doubts with EduRev
Most Upvoted Answer
In the gaseous equilibriumthe formation ofwill be favored by a)High...
Acccoding to vant hoff equation; endothermic rxns gets forwarded at higher temperature.Also, according to le chatelier principle; when pressure is increased, equilibrium will shift towards less no. Of gaseous species to neglify the change.
Explore Courses for JEE exam

Similar JEE Doubts

In the Figure, isotherms of CO2 at several temperatures near the critical point are shown. At the critical point (critical stat e), the distinction between the liquid and gaseous states disappear and the density of the gaseous substance is equal to that in the liquid state. For every gas this occurs at specific values of temperature and pressure, called critical temperature and critical pressure respectively. At temperatures and pressures above the critical point value, a gas is said be in a supercritical state. Critical constants are evaluated by solving the Vander W aals equation which is a cubic involume. The values are TcIn the supercritical region the behaviour is studied by plotting Z vs P plots. The variation in this region is studied with respect to boyles temperature aAt temperaturehigher than CB the variation is linear (Plot I) and at temperature lower than CB the variation is non linear (Plot II) With reference to the passage answers the following questions:Q.Which statement(s) about the behaviour of a real gas is/are wrong?

Sketch shows the plot of Z v/s P for of a hypothetical gas for one mole at three distinct temperature.Boyles temperature is the temperature at which a gas shows ideal behaviour over a pressure range in the low pressure region. Boyles temperature (T b) = a/Rb . If a plot is obtained at temperatures well below Boyles temperature then the curve will show negative deviation, in low pressure region and positive deviation in the high pressure region. Near critical temperature the curve is more likely as CO2 and the temperature well above critical temperature curve is more like H2 at 0C as shown above. At high pressure suppose all the constant temperature curve varies linearly with pressure according to the following equation:Q.For 500 K plot value of Z changes from 2 to 2.2 if pressure is varied from 1000 atm to 1200 atm (high pressur e) then the value of b/RTwill be

Sketch shows the plot of Z v/s P for of a hypothetical gas for one mole at three distinct temperature.Boyles temperature is the temperature at which a gas shows ideal behaviour over a pressure range in the low pressure region. Boyles temperature (T b) = a/Rb . If a plot is obtained at temperatures well below Boyles temperature then the curve will show negative deviation, in low pressure region and positive deviation in the high pressure region. Near critical temperature the curve is more likely as CO2 and the temperature well above critical temperature curve is more like H2 at 0C as shown above. At high pressure suppose all the constant temperature curve varies linearly with pressure according to the following equation:Q.As shown in the figure at 200 K and 500 atm value of compressibility factor is 2 (approx). Then volume of the gas at this point will be

Top Courses for JEEView all

Top Courses for JEE

In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer?
Question Description
In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer?.
Solutions for In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an ample number of questions to practice In the gaseous equilibriumthe formation ofwill be favored by a)High pressure and low temperatureb)High temperature and low pressurec)Low temperature and low pressured)High temperature and high pressureCorrect answer is option 'D'. Can you explain this answer? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses
SaveJoin the Discussion on the App for FREE
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup