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The major product obtained when isobutane is
treated with chlorine in the presence of light is
- a)Isobutyl chloride
- b)n-Butyl chloride
- c)tert-Butyl chloride
- d)sec-Butyl chloride
Correct answer is option 'C'. Can you explain this answer?
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The major product obtained when isobutane istreated with chlorine in t...
Reaction Mechanism:
The reaction of isobutane with chlorine in the presence of light is an example of free radical halogenation. The mechanism of this reaction is as follows:
1. Initiation: Chlorine molecule absorbs light energy and breaks down into two chlorine free radicals (each with one unpaired electron).
Cl2 + hv → 2Cl•
2. Propagation: The chlorine free radical reacts with isobutane to form an isobutyl radical and a hydrogen chloride molecule. The isobutyl radical then reacts with another chlorine molecule to form tert-butyl chloride and a chlorine free radical.
Cl• + (CH3)3CH → (CH3)3C• + HCl
(CH3)3C• + Cl2 → (CH3)3CCl + Cl•
3. Termination: The reaction terminates when two free radicals combine to form a stable product.
Cl• + Cl• → Cl2
Explanation:
In the given reaction, isobutane is treated with chlorine in the presence of light. The chlorine molecule undergoes homolytic cleavage to form two chlorine free radicals. These free radicals then react with isobutane to form isobutyl radicals and hydrogen chloride molecules. The isobutyl radical then reacts with another chlorine molecule to form tert-butyl chloride and a chlorine free radical.
Since the reaction proceeds through a free radical mechanism, the product obtained depends on the stability of the free radicals involved. Among the four possible isomers of butyl chloride, tert-butyl chloride is the most stable due to the presence of three methyl groups on the tertiary carbon atom, which provide steric hindrance to the attacking free radical. Hence, the major product obtained in the given reaction is tert-butyl chloride.
The reaction of isobutane with chlorine in the presence of light is an example of free radical halogenation. The mechanism of this reaction is as follows:
1. Initiation: Chlorine molecule absorbs light energy and breaks down into two chlorine free radicals (each with one unpaired electron).
Cl2 + hv → 2Cl•
2. Propagation: The chlorine free radical reacts with isobutane to form an isobutyl radical and a hydrogen chloride molecule. The isobutyl radical then reacts with another chlorine molecule to form tert-butyl chloride and a chlorine free radical.
Cl• + (CH3)3CH → (CH3)3C• + HCl
(CH3)3C• + Cl2 → (CH3)3CCl + Cl•
3. Termination: The reaction terminates when two free radicals combine to form a stable product.
Cl• + Cl• → Cl2
Explanation:
In the given reaction, isobutane is treated with chlorine in the presence of light. The chlorine molecule undergoes homolytic cleavage to form two chlorine free radicals. These free radicals then react with isobutane to form isobutyl radicals and hydrogen chloride molecules. The isobutyl radical then reacts with another chlorine molecule to form tert-butyl chloride and a chlorine free radical.
Since the reaction proceeds through a free radical mechanism, the product obtained depends on the stability of the free radicals involved. Among the four possible isomers of butyl chloride, tert-butyl chloride is the most stable due to the presence of three methyl groups on the tertiary carbon atom, which provide steric hindrance to the attacking free radical. Hence, the major product obtained in the given reaction is tert-butyl chloride.
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The major product obtained when isobutane istreated with chlorine in the presence of light isa)Isobutyl chlorideb)n-Butyl chloridec)tert-Butyl chlorided)sec-Butyl chlorideCorrect answer is option 'C'. Can you explain this answer?
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The major product obtained when isobutane istreated with chlorine in the presence of light isa)Isobutyl chlorideb)n-Butyl chloridec)tert-Butyl chlorided)sec-Butyl chlorideCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The major product obtained when isobutane istreated with chlorine in the presence of light isa)Isobutyl chlorideb)n-Butyl chloridec)tert-Butyl chlorided)sec-Butyl chlorideCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The major product obtained when isobutane istreated with chlorine in the presence of light isa)Isobutyl chlorideb)n-Butyl chloridec)tert-Butyl chlorided)sec-Butyl chlorideCorrect answer is option 'C'. Can you explain this answer?.
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