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Chlorobenzene can be prepared by reacting aniline with :             (1984 - 1 Mark)
  • a)
    hydrochloric acid
  • b)
    cuprous chloride
  • c)
    chlorine in presence of anhydrous aluminium chloride
  • d)
    nitrous acid followed by heating with cuprous chloride
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Chlorobenzene can be prepared by reacting aniline with : (1984 - ...
Chlorobenze can be prepared by reacting with nitrous acid followed by heating and cuprous chloride.
The first step is the formation of diazonium salt.
The second step is sanmeyer reaction in which a diazonium group is replaced by chloro group.
Thus the end result of this reactio would be obtained as chlorobenzene.
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Most Upvoted Answer
Chlorobenzene can be prepared by reacting aniline with : (1984 - ...
Preparation of Chlorobenzene from Aniline:

Reaction: Aniline + Nitrous Acid -> Benzenediazonium chloride + Water

Step 1: Conversion of Aniline to Benzenediazonium chloride
Aniline reacts with nitrous acid (HNO2) to form a highly reactive intermediate called benzenediazonium chloride. This reaction is known as diazotization.

Step 2: Conversion of Benzenediazonium chloride to Chlorobenzene
The benzenediazonium chloride is then heated with cuprous chloride (CuCl) to give chlorobenzene. This reaction is known as Sandmeyer reaction.

Explanation:
- Aniline (C6H5NH2) is treated with nitrous acid (HNO2) to form benzenediazonium chloride (C6H5N2Cl).
- Nitrous acid is generated in situ by the reaction of sodium nitrite (NaNO2) with hydrochloric acid (HCl).
- The diazotization reaction involves the replacement of the amino group (-NH2) of aniline with a diazonium group (-N2Cl).
- The reaction proceeds via the formation of a diazonium ion intermediate, which is then converted to the diazonium chloride salt in the presence of hydrochloric acid.
- The benzenediazonium chloride obtained is unstable and highly reactive.
- It can undergo various substitution reactions to form different products.
- In this case, it is heated with cuprous chloride (CuCl) to give chlorobenzene (C6H5Cl).
- The Sandmeyer reaction involves the replacement of the diazonium group with a chlorine atom, resulting in the formation of chlorobenzene.
- Cuprous chloride acts as a catalyst in this reaction, facilitating the substitution of the diazonium group.
- The reaction is carried out in an inert solvent such as ether or benzene.
- The overall reaction can be represented as:
C6H5N2Cl + CuCl -> C6H5Cl + N2 + CuCl2

Key Points:
- Aniline is converted to benzenediazonium chloride by diazotization with nitrous acid.
- Benzenediazonium chloride is then heated with cuprous chloride to give chlorobenzene.
- Nitrous acid is generated in situ by the reaction of sodium nitrite with hydrochloric acid.
- Cuprous chloride acts as a catalyst in the Sandmeyer reaction.
- The Sandmeyer reaction involves the substitution of the diazonium group with a chlorine atom.
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Chlorobenzene can be prepared by reacting aniline with : (1984 - 1 Mark)a)hydrochloric acidb)cuprous chloridec)chlorine in presence of anhydrous aluminium chlorided)nitrous acid followed by heating with cuprous chlorideCorrect answer is option 'D'. Can you explain this answer?
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Chlorobenzene can be prepared by reacting aniline with : (1984 - 1 Mark)a)hydrochloric acidb)cuprous chloridec)chlorine in presence of anhydrous aluminium chlorided)nitrous acid followed by heating with cuprous chlorideCorrect answer is option 'D'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Chlorobenzene can be prepared by reacting aniline with : (1984 - 1 Mark)a)hydrochloric acidb)cuprous chloridec)chlorine in presence of anhydrous aluminium chlorided)nitrous acid followed by heating with cuprous chlorideCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Chlorobenzene can be prepared by reacting aniline with : (1984 - 1 Mark)a)hydrochloric acidb)cuprous chloridec)chlorine in presence of anhydrous aluminium chlorided)nitrous acid followed by heating with cuprous chlorideCorrect answer is option 'D'. Can you explain this answer?.
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