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An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The resistance of the circuit is negligible. The energy stored in the circuit is completely magnetic at time (in milli seconds) being measured from the instant when the circuit is closed
  • a)
    1.57,4.71,7.85
  • b)
    1.57,3.14,4.71
  • c)
    0,1.57,4.71
  • d)
    None of these
Correct answer is option 'A'. Can you explain this answer?
Verified Answer
An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The...
When R is negigible,
Therefore, t = 1.57, 4.71, 7.85 ... milli sec
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An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The...
When R is negigible,
Therefore, t = 1.57, 4.71, 7.85 ... milli sec
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Community Answer
An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The...
Understanding the L.C. Circuit
An L.C. circuit consists of an inductor (L) and a capacitor (C). In this case, we have:
- Inductor (L) = 10 mH = 0.01 H
- Capacitor (C) = 25 µF = 25 x 10^-6 F
Energy in L.C. Circuit
The energy stored in the circuit oscillates between the capacitor and the inductor. Initially, when the circuit is closed, all energy is stored as electric energy in the capacitor.
The total energy (E) in the circuit can be calculated using the formula:
E = (1/2) * C * V^2
However, as the circuit oscillates, the energy transfers from the capacitor to the inductor and vice versa.
Time Period of Oscillation
The time period (T) of oscillation can be derived from:
T = 2 * π * √(L * C)
Substituting the values:
- L = 0.01 H
- C = 25 x 10^-6 F
Calculating T gives:
T ≈ 0.01 s = 10 ms
Energy Distribution Over Time
1. At t = 0 ms: All energy is in the capacitor.
2. At t = 2.5 ms: Energy is equally distributed.
3. At t = 5 ms: All energy is in the inductor.
4. At t = 7.5 ms: Energy is again equally distributed.
5. At t = 10 ms: All energy returns to the capacitor.
Key Times for Magnetic Energy
- Magnetic energy is maximum at the time when the entire energy is in the inductor:
- t = 5 ms (1.57 ms, 4.71 ms, 7.85 ms correspond to the oscillation points).
Thus, the correct answer is option 'A': 1.57, 4.71, 7.85 ms, as these are the times when the energy is completely magnetic.
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An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The resistance of the circuit is negligible. The energy stored in the circuit is completely magnetic at time (in milli seconds) being measured from the instant when the circuit is closeda)1.57,4.71,7.85b)1.57,3.14,4.71c)0,1.57,4.71d)None of theseCorrect answer is option 'A'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The resistance of the circuit is negligible. The energy stored in the circuit is completely magnetic at time (in milli seconds) being measured from the instant when the circuit is closeda)1.57,4.71,7.85b)1.57,3.14,4.71c)0,1.57,4.71d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An L.C. circuit contains 10 mH inductor and a 25 μ F capacitor. The resistance of the circuit is negligible. The energy stored in the circuit is completely magnetic at time (in milli seconds) being measured from the instant when the circuit is closeda)1.57,4.71,7.85b)1.57,3.14,4.71c)0,1.57,4.71d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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