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MnCr2O4 is:
- a)Normal spinel wit h total CFSE of –15.5 Dq.
- b)Inverse spinel wit h total CFSE of –15.5 Dq.
- c)Normal spinel wit h total CFSE of –24 Dq.
- d)Inverse spinel wit h total CFSE of –24 Dq.
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Invers...
In the normal spinel structure, MnCr₂O₄ is arranged as (Mn²⁺) tetrahedral (Cr³⁺)₂ Octahedral. The O²⁻ ions act as weak field ligands.
- For Mn²⁺ (d⁵ configuration), the ion is in a high-spin state. Therefore, its CFSE = 0.
- For Cr³⁺ (d³ configuration) in an octahedral field, the CFSE = -12 Dq per Cr³⁺ ion.
Since there are two Cr³⁺ ions, the total CFSE contributed by Cr³⁺ ions is:
2 × (-12 Dq) = -24 Dq.
Adding these contributions:
CFSE of Mn²⁺ + CFSE of Cr³⁺ = 0 + (-24 Dq) = -24 Dq.
CFSE of Mn²⁺ + CFSE of Cr³⁺ = 0 + (-24 Dq) = -24 Dq.
Thus, MnCr₂O₄ is a normal spinel with a total CFSE of -24 Dq, making Option C correct.
Most Upvoted Answer
MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Invers...
In normal spinal structure it should be (Mn2+)tetra (Cr3+)2 octa ...O2- is weak field ligand ...for Mn2+ it is high spin d5 so CFSE = 0. for one Cr3+ octahedral it is t2g 3 ..so CFSE = -question 12 Dq...for 2 Cr3+ it is -24 Dq ...so total = 0+ (-24)Dq = -24 Dq
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MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Invers...
Total CFSE of MnCr2O4
MnCr2O4 is a type of spinel compound that contains both Mn and Cr ions. The total CFSE (Crystal Field Stabilization Energy) of this compound is an important factor in determining its properties and behavior.
Normal spinel vs Inverse spinel
Spinel compounds can be either normal or inverse, depending on the distribution of metal ions in the crystal structure. In a normal spinel, the divalent metal ions occupy the octahedral sites, while the trivalent metal ions occupy the tetrahedral sites. In an inverse spinel, the opposite is true - the divalent metal ions occupy the tetrahedral sites, while the trivalent metal ions occupy the octahedral sites.
CFSE in MnCr2O4
The total CFSE of MnCr2O4 is 24 Dq. This indicates that it is a normal spinel, as the CFSE of an inverse spinel would be 15.5 Dq. The CFSE of a normal spinel is higher than that of an inverse spinel, due to the arrangement of the metal ions in the crystal structure.
Importance of CFSE in spinel compounds
The CFSE of spinel compounds plays a crucial role in determining their magnetic, electrical, and optical properties. It can also affect their stability and reactivity. By understanding the CFSE of a spinel compound, we can gain insight into its behavior and potential applications in various fields.
MnCr2O4 is a type of spinel compound that contains both Mn and Cr ions. The total CFSE (Crystal Field Stabilization Energy) of this compound is an important factor in determining its properties and behavior.
Normal spinel vs Inverse spinel
Spinel compounds can be either normal or inverse, depending on the distribution of metal ions in the crystal structure. In a normal spinel, the divalent metal ions occupy the octahedral sites, while the trivalent metal ions occupy the tetrahedral sites. In an inverse spinel, the opposite is true - the divalent metal ions occupy the tetrahedral sites, while the trivalent metal ions occupy the octahedral sites.
CFSE in MnCr2O4
The total CFSE of MnCr2O4 is 24 Dq. This indicates that it is a normal spinel, as the CFSE of an inverse spinel would be 15.5 Dq. The CFSE of a normal spinel is higher than that of an inverse spinel, due to the arrangement of the metal ions in the crystal structure.
Importance of CFSE in spinel compounds
The CFSE of spinel compounds plays a crucial role in determining their magnetic, electrical, and optical properties. It can also affect their stability and reactivity. By understanding the CFSE of a spinel compound, we can gain insight into its behavior and potential applications in various fields.
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MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer?.
MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer? for Chemistry 2025 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Chemistry 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for MnCr2O4 is:a)Normal spinel wit h total CFSE of –15.5 Dq.b)Inverse spinel wit h total CFSE of –15.5 Dq.c)Normal spinel wit h total CFSE of –24 Dq.d)Inverse spinel wit h total CFSE of –24 Dq.Correct answer is option 'C'. Can you explain this answer?.
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