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An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3 is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1 of the heights of the liquid in the two arms ?
                   
  • a)
     3/1
  • b)
    5/2
  • c)
    2/1
  • d)
    3/2
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
An open-ended U-tube of uniform cross-sectional area contains water (d...
5 × 4 × 10 + (h1 - 5) × 10 = h2 × 1 × 10
200 + 10h1 – 50 = 10h2
10h2 - 10h1 = 150
h2 - h1 = 15
h2 + h1 = 20 + 20 + 5 = 45
2h2 = 60
h2 = 30
h1 = 15
h2/h1 = 30/15
h2/h1 = 2/1
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Most Upvoted Answer
An open-ended U-tube of uniform cross-sectional area contains water (d...
5×4×10+(h1-5)×10=h2×1×10
200+10h1-50=10h2
10h2-10h1=150
h2-h1=15
h2+h1=20+20+5=45
2h2=60
h2=30
h1=15
h2/h1=30/15
h2/h1=2/1
hence option c is correct
Free Test
Community Answer
An open-ended U-tube of uniform cross-sectional area contains water (d...
5 × 4 × 10 + (h1 - 5) × 10 = h2 × 1 × 10
200 + 10h1 – 50 = 10h2
10h2 - 10h1 = 150
h2 - h1 = 15
h2 + h1 = 20 + 20 + 5 = 45
2h2 = 60
h2 = 30
h1 = 15
h2/h1 = 30/15
h2/h1 = 2/1
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An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1of the heights of the liquid in the two arms ? a)3/1b)5/2c)2/1d)3/2Correct answer is option 'C'. Can you explain this answer?
Question Description
An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1of the heights of the liquid in the two arms ? a)3/1b)5/2c)2/1d)3/2Correct answer is option 'C'. Can you explain this answer? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1of the heights of the liquid in the two arms ? a)3/1b)5/2c)2/1d)3/2Correct answer is option 'C'. Can you explain this answer? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for An open-ended U-tube of uniform cross-sectional area contains water (density 1.0 gram/centimeter3) standing initially 20 centimeters from the bottom in each arm. An immiscible liquid of density 4.0 grams/centimeter3is added to one arm until a layer 5 centimeters high forms, as shown in the figure above. What is the ratio h2/h1of the heights of the liquid in the two arms ? a)3/1b)5/2c)2/1d)3/2Correct answer is option 'C'. Can you explain this answer?.
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