Chemistry Exam > Chemistry Questions > Among the following donors, the one that form...
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Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:
- a)4–Methylpyridine
- b)2,6–Dimethylpyridine
- c)4–Nitropyridine
- d)2,6–Di–tert–butylpyridine
Correct answer is option 'A'. Can you explain this answer?
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Among the following donors, the one that forms most stable adduct with...
The more the election density on nitrogen more stable adduct will form with Lewis acid.but in case of b and d part crowding increases so stability decrease. so a part will be the answer.
Hope ,this will help you.
Hope ,this will help you.
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Among the following donors, the one that forms most stable adduct with...
Lewis Acid-Base Reaction
A Lewis acid is an electron-pair acceptor while a Lewis base is an electron-pair donor. When a Lewis acid and a Lewis base react, they form an adduct. The stability of the adduct depends on the strength of the bond between the Lewis acid and the Lewis base.
Donor Molecules
In this question, we are given four donor molecules: 4-methylpyridine, 2,6-dimethylpyridine, 4-nitropyridine, and 2,6-di-tert-butylpyridine. We need to determine which of these molecules forms the most stable adduct with the Lewis acid B(CH3)3.
Answer Explanation
The correct answer is option 'A', which is 4-methylpyridine. This is because 4-methylpyridine has a lone pair of electrons on the nitrogen atom, which can donate to the Lewis acid B(CH3)3. The resulting adduct is stabilized by the formation of a coordinate covalent bond between the nitrogen atom of the donor molecule and the boron atom of the Lewis acid.
The other donor molecules in the question also have lone pairs of electrons on the nitrogen atom, but they are less effective at donating electrons to the Lewis acid. This is because they have other substituents on the pyridine ring that can hinder the donation of electrons. For example, 2,6-dimethylpyridine has two methyl groups that can interfere with the donation of electrons.
Conclusion
In conclusion, the donor molecule that forms the most stable adduct with the Lewis acid B(CH3)3 is 4-methylpyridine. This is because it has a lone pair of electrons on the nitrogen atom, which can donate to the Lewis acid and form a stable coordinate covalent bond.
A Lewis acid is an electron-pair acceptor while a Lewis base is an electron-pair donor. When a Lewis acid and a Lewis base react, they form an adduct. The stability of the adduct depends on the strength of the bond between the Lewis acid and the Lewis base.
Donor Molecules
In this question, we are given four donor molecules: 4-methylpyridine, 2,6-dimethylpyridine, 4-nitropyridine, and 2,6-di-tert-butylpyridine. We need to determine which of these molecules forms the most stable adduct with the Lewis acid B(CH3)3.
Answer Explanation
The correct answer is option 'A', which is 4-methylpyridine. This is because 4-methylpyridine has a lone pair of electrons on the nitrogen atom, which can donate to the Lewis acid B(CH3)3. The resulting adduct is stabilized by the formation of a coordinate covalent bond between the nitrogen atom of the donor molecule and the boron atom of the Lewis acid.
The other donor molecules in the question also have lone pairs of electrons on the nitrogen atom, but they are less effective at donating electrons to the Lewis acid. This is because they have other substituents on the pyridine ring that can hinder the donation of electrons. For example, 2,6-dimethylpyridine has two methyl groups that can interfere with the donation of electrons.
Conclusion
In conclusion, the donor molecule that forms the most stable adduct with the Lewis acid B(CH3)3 is 4-methylpyridine. This is because it has a lone pair of electrons on the nitrogen atom, which can donate to the Lewis acid and form a stable coordinate covalent bond.
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Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer?
Question Description
Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer?.
Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? for Chemistry 2024 is part of Chemistry preparation. The Question and answers have been prepared according to the Chemistry exam syllabus. Information about Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Chemistry 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for Chemistry.
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Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Among the following donors, the one that forms most stable adduct with the Lewis acid B(CH3)3 is:a)4–Methylpyridineb)2,6–Dimethylpyridinec)4–Nitropyridined)2,6–Di–tert–butylpyridineCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
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