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Two coherent sources of intensity ratio 100:1 interfere. The ratio of interference at the maxima and minima​
  • a)
    120:81 cm
  • b)
    121:81 cm
  • c)
    3:1 cm
  • d)
    121:85 cm
Correct answer is option 'B'. Can you explain this answer?
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Interference of Coherent Sources

When two coherent sources interfere, the resultant intensity is given by

I = I1 + I2 + 2√(I1I2)cos⁡(δ)

where I1 and I2 are the intensities of the individual sources, δ is the phase difference between them.

Intensity Ratio

The intensity ratio of two coherent sources is given by

R = I1/I2

Squaring both sides, we get

R^2 = I1/I2

R^2 - 1 = (I1 - I2)/I2

(I1 - I2)/I2 = (R^2 - 1)

(I1 - I2) = I2(R^2 - 1)

(I1 - I2)/I1 = (1 - 1/R^2)

(1 - 1/R^2) is the fractional difference in the intensities of the two sources.

Ratio of Interference at Maxima and Minima

At the maxima, cos(δ) = 1, so the interference term is at its maximum value. At the minima, cos(δ) = -1, so the interference term is at its minimum value. Thus, the ratio of interference at the maxima and minima is given by

(I1 + I2 + 2√(I1I2))/(I1 + I2 - 2√(I1I2)) = [(1 + √R)/(1 - √R)]^2

Substituting R = 100, we get

[(1 + √100)/(1 - √100)]^2 = (121/81)

Therefore, the correct option is B, 121:81 cm.
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Two coherent sources of intensity ratio 100:1 interfere. The ratio of interference at the maxima and minima​a)120:81 cmb)121:81 cmc)3:1 cmd)121:85 cmCorrect answer is option 'B'. Can you explain this answer?
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