A polaroid is placed at 45° to an incoming light of intensity I0. Now the intensity of light passing through the poloroid after polarisation would be:a)zerob)I0/2c)I0d)I0/4Correct answer is option 'B'. Can you explain this answer?

Question

A polaroid is placed at 45&#176; to an incoming light of intensity I0. Now the intensity of light passing through the poloroid after polarisation would be:&#8203;a)zerob)I0/2c)I0d)I0/4Correct answer is option 'B'. Can you explain this answer?

Answer

Degrees to a linearly polarized light. The intensity of the transmitted light is reduced by half.

Explanation:

When a polaroid is placed at an angle of 45 degrees to the direction of polarization of a linearly polarized light, the intensity of the transmitted light is reduced by a factor of 2 (i.e., half). This happens because only the component of the polarization vector of the incident light that is parallel to the transmission axis of the polaroid is transmitted through it. When the polaroid is at an angle of 45 degrees to the incident light, the polarization vector of the incident light is split into two components, one parallel and one perpendicular to the transmission axis of the polaroid. Since the perpendicular component is blocked by the polaroid, only the parallel component is transmitted, resulting in a reduction of the intensity of the transmitted light by half.

Answer

We know that I=Io (cos)² theta).here theta=45degree.so,cos (1/√2)² it gives 1/2 and it gives
Io/2

Answer

As the light ray passes through the polaroid the intensity becomes half of initial because the polaroid allows the light component i.e. electric and magnetic of only specific

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