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One mole of a symmetrical alkane on ozonolysis gives two moles of an aldehyde having molecular mass of 44u. The alkene is
  • a)
    Ethene
  • b)
    Propene
  • c)
    1-butene
  • d)
    2-butene
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
One mole of a symmetrical alkane on ozonolysis gives two moles of an a...
One mole of a symmetrical alkene on ozonolysis gives two moles of an aldehyde having a molecular weight of mass of 44 u. The alkene is
CH3CH=CHCH3 +O3 ------2CH3CHO
molecular mass of CH3CHO is 12*2+4*1+16 =44
Thus the alkene is 2 butene and the aldehyde formed is ethanal(acetaldehyde)
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Community Answer
One mole of a symmetrical alkane on ozonolysis gives two moles of an a...
CH3-CH=CH-CH3 (2-butene) on ozonolysis will give CH3-CHO (acetaldehyde) which has molecular mass of 44u.
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