Class 11 Exam > Class 11 Questions > when 100ml of solution of H2O2 reacts complet...
Start Learning for Free
when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2
Verified Answer
when 100ml of solution of H2O2 reacts completely with KI , then it oxi...
Meq of H2O2 = Meq of Na2S2O3 If N is normality of H2O2, then N � 25 = 0.3 � 20 ⇒ N = 0.24 ⇒ Volume strength = N � 5.6 = 1.334 V
This question is part of UPSC exam. View all Class 11 courses
Most Upvoted Answer
when 100ml of solution of H2O2 reacts completely with KI , then it oxi...
Calculation of Volume Strength of H2O2
Given Data:
- Initial volume of H2O2 solution = 100 ml
- Volume of Na2S2O3 required to react with liberated iodine = 25 ml
- Molarity of Na2S2O3 solution = 1 M
Step 1: Determining the moles of Iodine (I2) liberated
- From the reaction between H2O2 and KI, 1 mole of H2O2 liberates 1 mole of I2
- Volume of H2O2 solution = 100 ml = 0.1 L (as 1 L = 1000 ml)
- Number of moles of H2O2 = Molarity * Volume = 0.1 L * x M
- As per the reaction, moles of I2 = moles of H2O2 = 0.1x
Step 2: Determining the moles of Na2S2O3 required
- From the reaction between Na2S2O3 and I2, 1 mole of Na2S2O3 reacts with 1 mole of I2
- Moles of Na2S2O3 = Molarity * Volume = 1 * 0.025 L = 0.025 mol
Step 3: Calculation of Volume Strength of H2O2
- From Step 1, moles of I2 liberated = 0.1x
- From Step 2, moles of Na2S2O3 required = 0.025
- Since 1 mole of I2 reacts with 1 mole of Na2S2O3, moles of I2 = moles of Na2S2O3
- Therefore, 0.1x = 0.025
- Solving for x, we get x = 0.25 M
Result:
- The volume strength of the H2O2 solution is 0.25 M.
Given Data:
- Initial volume of H2O2 solution = 100 ml
- Volume of Na2S2O3 required to react with liberated iodine = 25 ml
- Molarity of Na2S2O3 solution = 1 M
Step 1: Determining the moles of Iodine (I2) liberated
- From the reaction between H2O2 and KI, 1 mole of H2O2 liberates 1 mole of I2
- Volume of H2O2 solution = 100 ml = 0.1 L (as 1 L = 1000 ml)
- Number of moles of H2O2 = Molarity * Volume = 0.1 L * x M
- As per the reaction, moles of I2 = moles of H2O2 = 0.1x
Step 2: Determining the moles of Na2S2O3 required
- From the reaction between Na2S2O3 and I2, 1 mole of Na2S2O3 reacts with 1 mole of I2
- Moles of Na2S2O3 = Molarity * Volume = 1 * 0.025 L = 0.025 mol
Step 3: Calculation of Volume Strength of H2O2
- From Step 1, moles of I2 liberated = 0.1x
- From Step 2, moles of Na2S2O3 required = 0.025
- Since 1 mole of I2 reacts with 1 mole of Na2S2O3, moles of I2 = moles of Na2S2O3
- Therefore, 0.1x = 0.025
- Solving for x, we get x = 0.25 M
Result:
- The volume strength of the H2O2 solution is 0.25 M.
Attention Class 11 Students!
To make sure you are not studying endlessly, EduRev has designed Class 11 study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Class 11.
|
|
Explore Courses for Class 11 exam
|
|
Similar Class 11 Doubts
Top Courses for Class 11View all
when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2
Question Description
when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2.
when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2.
Solutions for when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 in English & in Hindi are available as part of our courses for Class 11.
Download more important topics, notes, lectures and mock test series for Class 11 Exam by signing up for free.
Here you can find the meaning of when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 defined & explained in the simplest way possible. Besides giving the explanation of
when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2, a detailed solution for when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 has been provided alongside types of when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 theory, EduRev gives you an
ample number of questions to practice when 100ml of solution of H2O2 reacts completely with KI , then it oxidises KI into I2 . Now liberated iodine required 25ml of 1M Na2S2O3 in basic medium , where it oxidises into SO4 2negative , then what is the volume strength of H2O2 tests, examples and also practice Class 11 tests.
|
|
Explore Courses for Class 11 exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup