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Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)
- a)ntRT/K2
- b)n2RT/K2p2
- c)n1RT/n2
- d)None of these
Correct answer is option 'A'. Can you explain this answer?
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Relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is:
The relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is described by Henry's law. According to Henry's law, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
Henry's Law:
Henry's law states that at a constant temperature, the amount of gas (2) that dissolves in a given volume of solvent (1) is directly proportional to the partial pressure of gas (2) above the solvent. Mathematically, this can be represented as:
n2 = K2 * p2
where:
n2 = moles of gas (2) dissolved in the solvent (1)
K2 = Henry's constant for the specific gas-solvent system
p2 = partial pressure of gas (2) above the solvent (1)
Explanation:
When a gas is in contact with a liquid, the gas molecules exert a certain pressure on the liquid surface. This pressure is known as the partial pressure of the gas. According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure.
The proportionality constant, K2, known as Henry's constant, depends on the nature of the gas and the solvent. It represents the solubility of the gas in the solvent under a specific set of conditions, including temperature.
The equation n2 = K2 * p2 represents the direct relationship between the moles of gas dissolved (n2) and the partial pressure of the gas (p2). As the partial pressure of the gas increases, more gas molecules will dissolve in the liquid, increasing the moles of gas dissolved.
Conclusion:
In summary, the volume of gas (2) that dissolves in a fixed volume of solvent (1) is directly related to the partial pressure of the gas (2) according to Henry's law. The equation n2 = K2 * p2 represents this relationship, where K2 is the Henry's constant for the specific gas-solvent system.
The relation between the volume of gas (2) that dissolves in a fixed volume of solvent (1) and the partial pressure of gas (2) is described by Henry's law. According to Henry's law, the solubility of a gas in a liquid is directly proportional to the partial pressure of the gas above the liquid.
Henry's Law:
Henry's law states that at a constant temperature, the amount of gas (2) that dissolves in a given volume of solvent (1) is directly proportional to the partial pressure of gas (2) above the solvent. Mathematically, this can be represented as:
n2 = K2 * p2
where:
n2 = moles of gas (2) dissolved in the solvent (1)
K2 = Henry's constant for the specific gas-solvent system
p2 = partial pressure of gas (2) above the solvent (1)
Explanation:
When a gas is in contact with a liquid, the gas molecules exert a certain pressure on the liquid surface. This pressure is known as the partial pressure of the gas. According to Henry's law, the solubility of a gas in a liquid is directly proportional to its partial pressure.
The proportionality constant, K2, known as Henry's constant, depends on the nature of the gas and the solvent. It represents the solubility of the gas in the solvent under a specific set of conditions, including temperature.
The equation n2 = K2 * p2 represents the direct relationship between the moles of gas dissolved (n2) and the partial pressure of the gas (p2). As the partial pressure of the gas increases, more gas molecules will dissolve in the liquid, increasing the moles of gas dissolved.
Conclusion:
In summary, the volume of gas (2) that dissolves in a fixed volume of solvent (1) is directly related to the partial pressure of the gas (2) according to Henry's law. The equation n2 = K2 * p2 represents this relationship, where K2 is the Henry's constant for the specific gas-solvent system.
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Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer? for Class 12 2025 is part of Class 12 preparation. The Question and answers have been prepared according to the Class 12 exam syllabus. Information about Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for Class 12 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Relation between the volume of gas (2) that dissolves in a fixed volume of solvent(1) and the partial pressure of gas (2) is (nt = total moles, K1and K2 are Henry’s constants)a)ntRT/K2b)n2RT/K2p2c)n1RT/n2d)None of theseCorrect answer is option 'A'. Can you explain this answer?.
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