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Four particles, each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction. (Take that gravitational force between two point masses m1 and m2 separated by is   The speed of each particle is
  • a)
  • b)
  • c)
  • d)
Correct answer is option 'D'. Can you explain this answer?
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Four particles, each of mass M, move along a circle of radius R under ...
The resultant of these two forces is  .Now 
 
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Four particles, each of mass M, move along a circle of radius R under ...
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Four particles, each of mass M, move along a circle of radius R under ...
The net gravitational force = centripetal force

|F1| force between A and B

=GMM(2–√r)2
|F2| force between A and D

=GMM(2–√r)2
|F3| force between A and C

=GMM(2r)2
The components of F1 and F2 along the radius

|F1|cos45 and |F2|cos45[|F1|=|F2|=F]

Net force =2fcos45+F3

=2GM2(2–√r)2×12+GM24r


Mv20r=GM24r2[22–√+1]

v0=[GM4r(22–√+1)]1/2




Hence a is the orrect answer.
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Four particles, each of mass M, move along a circle of radius R under the action of their mutual gravitational attraction. (Take that gravitational force between two point masses m1 and m2 separated by is The speed of each particle isa)b)c)d)Correct answer is option 'D'. Can you explain this answer?
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