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A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.?
Most Upvoted Answer
A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius an...
Explanation:
Isothermal expansion is the process in which the temperature of the gas remains constant during the process of expansion or compression. The work done by the gas in an isothermal process is given by the formula:
W = nRT ln(V2/V1)
Where,
W = work done by the gas
n = number of moles
R = gas constant
T = temperature
V1 and V2 are the initial and final volumes of the gas.
Given data:
Initial volume, V1 = 10 dm^3
Final volume, V2 = 20 dm^3
Temperature, T = 27 degree Celsius = 300 K
Work done, W = 4.620 KJ
Calculation:
We can calculate the number of moles using the formula for work done as:
n = W/(RT ln(V2/V1))
Substituting the given values, we get:
n = (4.620 KJ)/(8.314 J/mol K * 300 K * ln(20/10))
n = 0.138 mol
Therefore, the number of moles is 0.138 mol.
Conclusion:
Thus, we can calculate the number of moles of a gas undergoing isothermal expansion using the formula for work done and the given values of initial and final volumes, temperature, and work done.
Isothermal expansion is the process in which the temperature of the gas remains constant during the process of expansion or compression. The work done by the gas in an isothermal process is given by the formula:
W = nRT ln(V2/V1)
Where,
W = work done by the gas
n = number of moles
R = gas constant
T = temperature
V1 and V2 are the initial and final volumes of the gas.
Given data:
Initial volume, V1 = 10 dm^3
Final volume, V2 = 20 dm^3
Temperature, T = 27 degree Celsius = 300 K
Work done, W = 4.620 KJ
Calculation:
We can calculate the number of moles using the formula for work done as:
n = W/(RT ln(V2/V1))
Substituting the given values, we get:
n = (4.620 KJ)/(8.314 J/mol K * 300 K * ln(20/10))
n = 0.138 mol
Therefore, the number of moles is 0.138 mol.
Conclusion:
Thus, we can calculate the number of moles of a gas undergoing isothermal expansion using the formula for work done and the given values of initial and final volumes, temperature, and work done.
Community Answer
A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius an...
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A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.?
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A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.?.
A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.? for Class 11 2024 is part of Class 11 preparation. The Question and answers have been prepared according to the Class 11 exam syllabus. Information about A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.? covers all topics & solutions for Class 11 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A gas expands isothermally from 10dm^3 to 20^3 at 27 degree Celsius and work obtained is 4.620 KJ. Find the no. of moles.?.
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