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Find the equation of the set of point P ,the sum of whose distances from A(4,0,0) B(-4,0,0) is equal to10 ?
Verified Answer
Find the equation of the set of point P ,the sum of whose distances fr...
Let the coordinates of P be (x, y, z).
The coordinates of points A and B are (4, 0, 0) and (–4, 0, 0) respectively.
It is given that PA + PB = 10.


On squaring both sides again, we obtain
25 (x2 + 8x + 16 + y2 + z2) = 625 + 16x2 + 200x
⇒ 25x2 + 200x + 400 + 25y2 + 25z2 = 625 + 16x2 + 200x
⇒ 9x2 + 25y2 + 25z2 – 225 = 0
Thus, the required equation is 9x2 + 25y2 + 25z2 – 225 = 0.
This question is part of UPSC exam. View all Commerce courses
Most Upvoted Answer
Find the equation of the set of point P ,the sum of whose distances fr...
Let the point P is (x,y,z)
Now given that
      PA + PB = 10
=> √{(x-4)2 + y2 + z2 } + √{(x+4)2+ y2 + z2 } = 10
=> √{(x-4)2 + y2 + z2 } = 10 - √{(x+4)2 + y2 + z2 }
Now square bothe side
     [√{(x-4)2 + y2 + z2 }]2 = (10)2 + [{(x+4)2 + y2 + z2 }]2 - 2 *10*√{(x+4)2 + y2 + z2 }
=> {(x-4)2 + y2 + z2 } = 100 + {(x+4)2 + y2 + z2 } - 20*√{(x+4)2+ y2 + z2 }
=> x2 + 16 - 8x + y2 + z2 = 100 + x2 + 16 + 8x + y2 + z2- 20*√{(x+4)2 + y2 + z2 }
=> - 8x = 100 +  8x - 20*√{(x+4)2+ y2 + z2 }
=> -8x -8x - 100 = - 20*√{(x+4)2 + y2 + z2 }
=> -16x -100 = - 20*√{(x+4)2 + y2+ z2 }
=> 4x + 25 = 5*√{(x+4)2 + y2 + z2}
Again square bothe side,
     (4x + 25)2 = 25 *[√{(x+4)2 + y2+ z2 }]2
=> 16x2 + 625 + 200x = 25*{(x+4)2 + y2 + z2 }
=> 16x2 + 625 + 200x = 25*(x2 + 16 + 8x + y2 + z2 )
=> 16x2 + 625 + 200x = 25x2 + 400 + 200x + 25y2 + 25z2
=> 25x2 + 400 + 200x + 25y2 + 25z2 - 16x2 - 625 - 200x = 0
=> 9x2 + 25y2 + 25z2 - 225 = 0 
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Find the equation of the set of point P ,the sum of whose distances from A(4,0,0) B(-4,0,0) is equal to10 ?
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