A rectangular tank of base area 100 m2 has a height of 2 m . Calculate...
The pressure due to a liquid in liquid columns of constant density at a depth is represented by the following formula:
Pressure = density of liquid X Acceleration due to gravity X height of the liquid
= 10^3 X 9.8 X 2 = 19600 N/m^2 [ since Acceleration due to gravity, g = 9.8m/s^2]
Thrust = Force = Pressure X Area = 19600 X 100 = 1,960,000N
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A rectangular tank of base area 100 m2 has a height of 2 m . Calculate...
Calculation of Thrust at the Bottom of the Tank
Given:
- Base area of the tank = 100 m^2
- Height of the tank = 2 m
- Density of water = 10^3 kg/m^3
To calculate the thrust at the bottom of the tank, we need to consider the weight of the water inside the tank and the pressure exerted by the water at the bottom.
Weight of the Water
The weight of an object can be calculated using the formula:
Weight = Mass x Gravity
In this case, the mass of the water can be calculated using the formula:
Mass = Volume x Density
The volume of the water can be calculated using the formula:
Volume = Base Area x Height
Substituting the given values, we can find the mass of the water:
Mass = (100 m^2) x (2 m) x (10^3 kg/m^3) = 200,000 kg
Now, we can calculate the weight of the water:
Weight = (200,000 kg) x (9.8 m/s^2) = 1,960,000 N
Pressure at the Bottom
Pressure is defined as the force exerted per unit area. In this case, the pressure at the bottom of the tank is the force exerted by the water divided by the area of the base.
The pressure can be calculated using the formula:
Pressure = Force / Area
Substituting the known values, we can find the pressure:
Pressure = (1,960,000 N) / (100 m^2) = 19,600 N/m^2
Thrust at the Bottom
The thrust at the bottom of the tank is equal to the pressure exerted by the water at the bottom.
Therefore, the thrust at the bottom of the tank is 19,600 N/m^2.
Summary:
- The weight of the water inside the tank is calculated by multiplying the volume of the water with its density.
- The pressure at the bottom of the tank is calculated by dividing the force exerted by the water by the area of the base.
- The thrust at the bottom of the tank is equal to the pressure exerted by the water at the bottom, which is 19,600 N/m^2.
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