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The number of moles of KMnO4 that will be needed to react with one mole of sulphite ion in acidic solution is:
- a)2/5
- b)3/5
- c)4/5
- d)1
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The number of moles of KMnO4 that will be needed to react with one mol...
To determine the number of moles of KMnO4 needed to react with one mole of sulphite ion in acidic solution, we need to balance the chemical equation for the reaction between KMnO4 and sulphite ion.
The balanced chemical equation for the reaction is as follows:
5SO3^2- + 2KMnO4 + 4H+ -> 5SO4^2- + 2Mn2+ + K2SO4 + 2H2O
From the balanced equation, we can see that 2 moles of KMnO4 are required to react with 5 moles of sulphite ion.
This can be expressed as a molar ratio:
2 moles KMnO4 : 5 moles SO3^2-
Since we are looking for the amount of KMnO4 required to react with 1 mole of sulphite ion, we can set up a proportion using the molar ratio:
2 moles KMnO4 / 5 moles SO3^2- = x moles KMnO4 / 1 mole SO3^2-
Simplifying the proportion:
2/5 = x/1
Cross-multiplying:
2 = 5x
Solving for x:
x = 2/5
Therefore, the number of moles of KMnO4 needed to react with one mole of sulphite ion in acidic solution is 2/5 moles.
The balanced chemical equation for the reaction is as follows:
5SO3^2- + 2KMnO4 + 4H+ -> 5SO4^2- + 2Mn2+ + K2SO4 + 2H2O
From the balanced equation, we can see that 2 moles of KMnO4 are required to react with 5 moles of sulphite ion.
This can be expressed as a molar ratio:
2 moles KMnO4 : 5 moles SO3^2-
Since we are looking for the amount of KMnO4 required to react with 1 mole of sulphite ion, we can set up a proportion using the molar ratio:
2 moles KMnO4 / 5 moles SO3^2- = x moles KMnO4 / 1 mole SO3^2-
Simplifying the proportion:
2/5 = x/1
Cross-multiplying:
2 = 5x
Solving for x:
x = 2/5
Therefore, the number of moles of KMnO4 needed to react with one mole of sulphite ion in acidic solution is 2/5 moles.
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Community Answer
The number of moles of KMnO4 that will be needed to react with one mol...
The reaction will be
2KMnO4 + 5 H2SO3 --> K2SO4 +2 MnSO4 +2 H2SO4 + 3H2O
As 5 mole of sulphite reacts with 2 mole of KMnO4
Then 1 mole will react with 2/5 mole of KMnO4
2KMnO4 + 5 H2SO3 --> K2SO4 +2 MnSO4 +2 H2SO4 + 3H2O
As 5 mole of sulphite reacts with 2 mole of KMnO4
Then 1 mole will react with 2/5 mole of KMnO4
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