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A binary liquid solution is prepared by mixing n-heptaneand ethanol. Which one of the following statements iscorrect regarding the behaviour of the solution? [2009]
  • a)
    The solution is non-ideal, showing – ve deviation fromRaoult’s Law.
  • b)
    The solution is non-ideal, showing + ve deviation fromRaoult’s Law.
  • c)
    n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law.
  • d)
    The solution formed is an ideal solution.
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A binary liquid solution is prepared by mixing n-heptaneand ethanol. W...
(B) : The solution containing n-heptane and ethanol shows non-ideal behaviour with positive deviation from Raoult’s law. This is because the ethanol molecules are held together by strong H-bonds, however the forces between n-heptane and ethanol are not very strong, as a result they easily vapourise showing higher vapour presure than expected.
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A binary liquid solution is prepared by mixing n-heptaneand ethanol. W...
Understanding the Solution Behavior
When mixing n-heptane and ethanol, the behavior of the resulting binary liquid solution can be analyzed through Raoult's Law and the concept of ideal versus non-ideal solutions.
Raoult's Law Overview
- Raoult's Law states that the partial vapor pressure of each component in an ideal solution is proportional to its mole fraction.
- Deviations from this law occur in real solutions due to interactions between different molecules.
Nature of n-Heptane and Ethanol
- n-Heptane is a non-polar hydrocarbon, while ethanol is a polar molecule with hydrogen bonding capabilities.
- When mixed, these two solvents exhibit different strengths of intermolecular interactions.
Deviation from Raoult's Law
- The solution shows positive deviation from Raoult's Law, meaning that the vapor pressure of the solution is higher than expected.
- This is primarily due to the weaker interactions between n-heptane and ethanol compared to the stronger hydrogen bonding interactions present in pure ethanol or pure n-heptane.
Consequences of Positive Deviation
- The mixing of a polar and non-polar solvent results in a disruption of the strong intermolecular forces, leading to increased vapor pressure.
- This behavior indicates non-ideal characteristics, where the solution does not follow Raoult's Law strictly.
Conclusion
- The correct answer is option 'B': The solution is non-ideal, showing positive deviation from Raoult's Law.
- This highlights the importance of understanding molecular interactions in predicting solution behavior accurately.
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A binary liquid solution is prepared by mixing n-heptaneand ethanol. Which one of the following statements iscorrect regarding the behaviour of the solution? [2009]a)The solution is non-ideal, showing – ve deviation fromRaoult’s Law.b)The solution is non-ideal, showing + ve deviation fromRaoult’s Law.c)n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law.d)The solution formed is an ideal solution.Correct answer is option 'B'. Can you explain this answer?
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A binary liquid solution is prepared by mixing n-heptaneand ethanol. Which one of the following statements iscorrect regarding the behaviour of the solution? [2009]a)The solution is non-ideal, showing – ve deviation fromRaoult’s Law.b)The solution is non-ideal, showing + ve deviation fromRaoult’s Law.c)n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law.d)The solution formed is an ideal solution.Correct answer is option 'B'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A binary liquid solution is prepared by mixing n-heptaneand ethanol. Which one of the following statements iscorrect regarding the behaviour of the solution? [2009]a)The solution is non-ideal, showing – ve deviation fromRaoult’s Law.b)The solution is non-ideal, showing + ve deviation fromRaoult’s Law.c)n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law.d)The solution formed is an ideal solution.Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A binary liquid solution is prepared by mixing n-heptaneand ethanol. Which one of the following statements iscorrect regarding the behaviour of the solution? [2009]a)The solution is non-ideal, showing – ve deviation fromRaoult’s Law.b)The solution is non-ideal, showing + ve deviation fromRaoult’s Law.c)n-heptane shows + ve deviation while ethanol shows– ve deviation from Raoult’s Law.d)The solution formed is an ideal solution.Correct answer is option 'B'. Can you explain this answer?.
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