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Assume a cube with mass m on each corner, what will the gravitational field due to the system of these masses at the centre of the cube?
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Assume a cube with mass m on each corner, what will the gravitational ...
Gravitational Field of a Cube with Masses at Corners
When analyzing the gravitational field at the center of a cube with mass m located at each corner, it is essential to consider the symmetry of the system.
Symmetry in the System
- The cube has eight corners, each occupied by a mass m.
- Due to the symmetrical arrangement, the gravitational forces exerted by each mass on the center will be equal in magnitude but opposite in direction.
Gravitational Force Calculation
- The gravitational force between two point masses is given by the formula F = G(m1 * m2) / r², where G is the gravitational constant, m1 and m2 are the masses, and r is the distance between them.
- In this case, the distance r from each corner mass to the center of the cube is constant.
Resultant Gravitational Field
- As the gravitational forces from the masses at the corners are directed towards the center, they will cancel out due to their equal and opposite nature.
- Specifically, for every mass pulling the center in one direction, there is an equal mass pulling it in the opposite direction.
Conclusion
- The net gravitational field at the center of the cube, therefore, sums to zero.
- This result highlights the principle of superposition in gravitational fields, where symmetrical distributions of mass lead to cancellation of their effects at specific points.
In summary, the gravitational field at the center of a cube with a mass at each corner is zero due to the equal and opposite gravitational forces from the symmetrically arranged masses.
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Assume a cube with mass m on each corner, what will the gravitational ...
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