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The dimension for a waveguide in dominant mode with a cut off wavelength of 2 units is
- a)2
- b)4
- c)6
- d)8
Correct answer is option 'B'. Can you explain this answer?
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The dimension for a waveguide in dominant mode with a cut off waveleng...
The cut off wavelength of a waveguide is given by λc = 2a/m. For the dominant mode, m = 1. Given that λc = 2, thus we get a = 4 units.
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The dimension for a waveguide in dominant mode with a cut off waveleng...
Answer: b
Explanation: The cut off wavelength of a waveguide is given by λc = 2a/m. For the dominant mode, m = 1. Given that λc = 2, thus we get a = 4 units.
Explanation: The cut off wavelength of a waveguide is given by λc = 2a/m. For the dominant mode, m = 1. Given that λc = 2, thus we get a = 4 units.
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The dimension for a waveguide in dominant mode with a cut off waveleng...
Explanation:
Waveguides are structures that are used to guide electromagnetic waves at microwave frequencies. The dominant mode in a waveguide is the mode with the lowest cutoff frequency. The cutoff wavelength is the wavelength below which the mode cannot propagate in the waveguide.
Given:
- Cutoff wavelength = 2 units
Calculation:
- The cutoff frequency is given by the formula: fc = c / λc, where c is the speed of light in vacuum and λc is the cutoff wavelength.
- The cutoff frequency corresponds to the lowest mode, which is the dominant mode in this case.
- For the dominant mode in a rectangular waveguide, the cutoff wavelength is given by the formula: λc = 2a, where a is the dimension of the waveguide.
Solving for a:
- Given λc = 2 units, we have 2 = 2a
- Dividing both sides by 2, we get a = 1 unit
Therefore, the dimension of the waveguide in the dominant mode is 2a = 2 * 1 = 4 units.
So, the correct answer is option B) 4.
Waveguides are structures that are used to guide electromagnetic waves at microwave frequencies. The dominant mode in a waveguide is the mode with the lowest cutoff frequency. The cutoff wavelength is the wavelength below which the mode cannot propagate in the waveguide.
Given:
- Cutoff wavelength = 2 units
Calculation:
- The cutoff frequency is given by the formula: fc = c / λc, where c is the speed of light in vacuum and λc is the cutoff wavelength.
- The cutoff frequency corresponds to the lowest mode, which is the dominant mode in this case.
- For the dominant mode in a rectangular waveguide, the cutoff wavelength is given by the formula: λc = 2a, where a is the dimension of the waveguide.
Solving for a:
- Given λc = 2 units, we have 2 = 2a
- Dividing both sides by 2, we get a = 1 unit
Therefore, the dimension of the waveguide in the dominant mode is 2a = 2 * 1 = 4 units.
So, the correct answer is option B) 4.
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The dimension for a waveguide in dominant mode with a cut off wavelength of 2 units isa)2b)4c)6d)8Correct answer is option 'B'. Can you explain this answer?
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