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The vertices A andB of an equilateral triangle of a side a have same charge q... calculate the electric field at point c of the triangle
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The vertices A andB of an equilateral triangle of a side a have same c...
The intensity (E) of electric field due to a point charge q located at the vertex A of equilateral ΔABC at vertex C at a distance a
E=14πϵoqa2
since, both the point-charges are equal in magnitude & equidistant from vertex C hence their electric fields will be equal in magnitude & making an acute angle 60∘ hence, the resultant electric field at the vertex C
=E2+E2+2E⋅Ecos60∘−−−−−−−−−−−−−−−−−−−√
=E3–√
=14πϵoq3√a2
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The vertices A andB of an equilateral triangle of a side a have same charge q... calculate the electric field at point c of the triangle Related: Electric Charges Introduction - Electric Charges and Field, Class 12, Physics
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