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The second order Bragg diffraction of X-rays with λ = 1.00 Å from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal is
- a)0.575 Å
- b)1.00 Å
- c)2.00 Å
- d)1.15 Å
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
The second order Bragg diffraction of X-rays with λ = 1.00 fro...
Bragg's Equation:
nλ=2d sin θ
Now, n=2,λ=1.00 ∘A,
θ=60∘,
d=?
⇒d=1sin 60∘
=>2√3
=>1.15 ∘A
nλ=2d sin θ
Now, n=2,λ=1.00 ∘A,
θ=60∘,
d=?
⇒d=1sin 60∘
=>2√3
=>1.15 ∘A
Most Upvoted Answer
The second order Bragg diffraction of X-rays with λ = 1.00 fro...
A wavelength of 1.54 Å occurs at an angle of 28.4°. What is the spacing between the planes of atoms in the crystal?
The Bragg diffraction equation relates the angle of diffraction (θ), the wavelength of the X-rays (λ), and the spacing between the planes of atoms (d):
2d sinθ = nλ
where n is an integer representing the order of diffraction.
For second order diffraction (n = 2), we can rearrange the equation to solve for d:
d = λ / 2 sinθ
Plugging in the given values, we get:
d = 1.54 Å / 2 sin(28.4°) = 2.82 Å
Therefore, the spacing between the planes of atoms in the crystal is 2.82 Angstroms.
The Bragg diffraction equation relates the angle of diffraction (θ), the wavelength of the X-rays (λ), and the spacing between the planes of atoms (d):
2d sinθ = nλ
where n is an integer representing the order of diffraction.
For second order diffraction (n = 2), we can rearrange the equation to solve for d:
d = λ / 2 sinθ
Plugging in the given values, we get:
d = 1.54 Å / 2 sin(28.4°) = 2.82 Å
Therefore, the spacing between the planes of atoms in the crystal is 2.82 Angstroms.
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The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer?.
The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer? for JEE 2025 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer? covers all topics & solutions for JEE 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The second order Bragg diffraction of X-rays with λ = 1.00 from a set of parallel planes in a metal occurs at an angle of 60°. The distance between the scattering planes in the crystal isa)0.575 b)1.00 c)2.00 d)1.15 Correct answer is option 'D'. Can you explain this answer?.
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