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Define the fundamental period of the following signal x[n] = exp(2pi*j*n/3) + exp(3*pi*j*n/4)?
  • a)
    8
  • b)
    12
  • c)
    18
  • d)
    24
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Define the fundamental period of the following signal x[n] = exp(2pi*j...
The first signal, will repeat itself after 3 cycles. The second will repeat itself after 8 cycles. Thus, both of them together will repeat themselves only after LCM(8,3) = 24 cycles.
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Define the fundamental period of the following signal x[n] = exp(2pi*j...
Fundamental Period of Signal x[n]

The fundamental period of a discrete-time signal is defined as the smallest positive integer value of N for which the signal repeats itself after N samples. In other words, if we shift the signal by N samples, the resulting signal is identical to the original signal.

Signal Definition

The given signal is x[n] = exp(2pi*j*n/3) * exp(3*pi*j*n/4) where j is the imaginary unit and n is an integer.

Analysis

To find the fundamental period of the signal, we need to determine the value of N such that x[n] = x[n+N] for all values of n. That is,

exp(2pi*j*n/3) * exp(3*pi*j*n/4) = exp(2pi*j*(n+N)/3) * exp(3*pi*j*(n+N)/4)

We can simplify this equation by canceling out the common factors and using the fact that exp(2pi*j) = 1. That is,

exp(3*pi*j*n/4) = exp(3*pi*j*(n+N)/4)

Taking the natural logarithm of both sides, we get

ln(exp(3*pi*j*n/4)) = ln(exp(3*pi*j*(n+N)/4))

3*pi*j*n/4 = 3*pi*j*(n+N)/4 + 2*k*pi*j where k is an integer

Simplifying this equation, we get

N = 12

Therefore, the fundamental period of the given signal is 12.
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