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A dice is thrown 3 times and the sum of the 3 numbers thrown is 15. The probability that the first throw was a four , is.?
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A dice is thrown 3 times and the sum of the 3 numbers thrown is 15. Th...
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A dice is thrown 3

times. If we add the outcomes, what is the maximum sum that we can get?
18
i.e.
6+6+6=18

But, we need to find the no. of ways in which we can get 15
i.e.
d1+d2+d3=15
To get 15, we need to subtract 3 from 18. (15=18−3)

Therefore, we need to find the no. of ways in which we can subtract 3
from the 3 outcomes(Each of the 3 outcomes are taken to be 6
which is nothing but, no. of non-negative solutions to the equation-
d1+d2+d3=3
no. of solutions to the above equation =

Therefore, there are total 10
possible outcomes in which we can get sum as 15

.Now, fixing the first outcome as 4
, we need to get 11 from the remaining 2 outcomes. We observe that there are only 2
such possibilities -
4+5+6=15
4+6+5=15

Therefore, required probability =
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A dice is thrown 3 times and the sum of the 3 numbers thrown is 15. The probability that the first throw was a four , is.?
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