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0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid.
A) 244g
B) 122g
C) 71g
D) 63g?
A) 244g
B) 122g
C) 71g
D) 63g?
Most Upvoted Answer
0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neu...
Given:
- Amount of monobasic acid = 0.305g
- Volume of NaOH used for complete neutralization = 25ml
- Concentration of NaOH = N/10
To Find:
Molecular mass of monobasic acid
Procedure:
1. Calculate the number of moles of NaOH used.
2. Use the stoichiometry of the reaction to determine the number of moles of monobasic acid used.
3. Calculate the molecular mass of the monobasic acid using the formula: molecular mass = mass / moles.
Calculation:
1. Calculate the number of moles of NaOH used:
- Concentration of NaOH = N/10 = 0.1 mol/L
- Volume of NaOH used = 25ml = 0.025L
- Number of moles of NaOH used = concentration × volume = 0.1 mol/L × 0.025L = 0.0025 mol
2. Determine the number of moles of monobasic acid used:
From the balanced chemical equation, we know that 1 mole of monobasic acid reacts with 1 mole of NaOH.
Therefore, the number of moles of monobasic acid used = 0.0025 mol.
3. Calculate the molecular mass of the monobasic acid:
- Mass of monobasic acid = 0.305g
- Molecular mass = mass / moles = 0.305g / 0.0025 mol = 122g/mol
Answer:
The molecular mass of the monobasic acid is 122g/mol. Therefore, the correct option is B) 122g.
- Amount of monobasic acid = 0.305g
- Volume of NaOH used for complete neutralization = 25ml
- Concentration of NaOH = N/10
To Find:
Molecular mass of monobasic acid
Procedure:
1. Calculate the number of moles of NaOH used.
2. Use the stoichiometry of the reaction to determine the number of moles of monobasic acid used.
3. Calculate the molecular mass of the monobasic acid using the formula: molecular mass = mass / moles.
Calculation:
1. Calculate the number of moles of NaOH used:
- Concentration of NaOH = N/10 = 0.1 mol/L
- Volume of NaOH used = 25ml = 0.025L
- Number of moles of NaOH used = concentration × volume = 0.1 mol/L × 0.025L = 0.0025 mol
2. Determine the number of moles of monobasic acid used:
From the balanced chemical equation, we know that 1 mole of monobasic acid reacts with 1 mole of NaOH.
Therefore, the number of moles of monobasic acid used = 0.0025 mol.
3. Calculate the molecular mass of the monobasic acid:
- Mass of monobasic acid = 0.305g
- Molecular mass = mass / moles = 0.305g / 0.0025 mol = 122g/mol
Answer:
The molecular mass of the monobasic acid is 122g/mol. Therefore, the correct option is B) 122g.
Community Answer
0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neu...
122g. is it correct
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0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g?
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0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g?.
0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about 0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 0.305g of a monobasic acid required 25ml of N/10 NaOH for complete neutralization. Find out molecular mass of monobasic acid. A) 244g B) 122g C) 71gD) 63g?.
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