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A car moves rectilinearly from station A(here car stops) to the next station B(here car also stops) with an acceleration according to law f=a-bx where a and b are positive constant and x is the distance from station A. If the maximum distance between the two stations is x=Na/b then find N ? N lies between 0 to 9?ans is 1? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A car moves rectilinearly from station A(here car stops) to the next station B(here car also stops) with an acceleration according to law f=a-bx where a and b are positive constant and x is the distance from station A. If the maximum distance between the two stations is x=Na/b then find N ? N lies between 0 to 9?ans is 1? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A car moves rectilinearly from station A(here car stops) to the next station B(here car also stops) with an acceleration according to law f=a-bx where a and b are positive constant and x is the distance from station A. If the maximum distance between the two stations is x=Na/b then find N ? N lies between 0 to 9?ans is 1?.

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