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Consider the following bromides :
 
  • a)
    Both decomposes to form 
  • b)
    Both decomposes to forms Br+
  • c)
    I decomposes to give and II gives Br+
  • d)
    I decomposes to give Br+ while II gives
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
Consider the following bromides : a)Both decomposes to formb)Both deco...
In the compound I, Br will dispatch as Br+ so that a -ve charge appears on carbon which will give us 6π electrons. So ring will become aromatic.(4n+2 π electron is needed for aromaticity)
In compound II, Br will dispatch as Br-. So that carbon has +ve charge and all the double bond will circulate in the ring. This will maintain 4n+2 π electron and the molecule will remain as aromatic.
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Most Upvoted Answer
Consider the following bromides : a)Both decomposes to formb)Both deco...
Because in 2and case if it decompose to Br+ then their aromaticity disturbed
.it become 8Π anti aromatic
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Community Answer
Consider the following bromides : a)Both decomposes to formb)Both deco...
In 1 structure Br+ formed then the ring become aromatic
in2 structure Br- formed then it's aromaticity donot get disturbed
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Consider the following bromides : a)Both decomposes to formb)Both decomposes to formsBr+c)I decomposes to give and II gives Br+d)I decomposes to give Br+ while II gives Correct answer is option 'D'. Can you explain this answer?
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