JEE Exam > JEE Questions > Assuming that Hund's rule is violated, th...
Start Learning for Free
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is
(2010, Single Option Correct Type)
- a)1 and diamagnetic
- b)0 and diamagnetic
- c)1 and paramagnetic
- d)0 and paramagnetic
Correct answer is option 'A'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Verified Answer
Assuming that Hund's rule is violated, the bond order and magnetic...
For molecules lighter than O2, the increasing ord er order of energies of molecular orbitals is :
Where, π2py and π2pz are degenerate molecular orbitals, first singly occupied and then pairing starts if Hund’s rule is obeyed. If Hund’s rule is violated in B2, electronic arrangement would be :
No unpaired electron-diamagnetic.
Most Upvoted Answer
Assuming that Hund's rule is violated, the bond order and magnetic...
To determine the bond order and magnetic nature of the diatomic molecule B2, we need to consider the electronic configuration of the molecule.
The atomic number of boron is 5, so the electronic configuration of a single boron atom is 1s^2 2s^2 2p^1. When two boron atoms combine to form a diatomic molecule, they share their valence electrons to form molecular orbitals.
- Hund's Rule violation:
Hund's Rule states that electrons occupy orbitals of the same energy level singly before pairing up. However, in the case of boron, the 2p orbital is not completely filled in the ground state configuration. This violates Hund's Rule as the electrons should first occupy separate orbitals before pairing up.
- Formation of molecular orbitals:
When two boron atoms combine, they form molecular orbitals by combining their atomic orbitals. The 2s orbitals of each boron atom combine to form two molecular orbitals: one bonding (σ) and one antibonding (σ*). The 2p orbitals also combine to form two molecular orbitals: one bonding (π) and one antibonding (π*).
- Bond order calculation:
The bond order is given by the difference between the number of bonding and antibonding electrons divided by 2. In the case of B2, the molecular orbital diagram can be represented as:
σ2s^2 σ*2s^2 π2p^2 π*2p^0
The number of bonding electrons is 4 (2 from σ2s and 2 from π2p), and the number of antibonding electrons is 2 (from σ*2s). Therefore, the bond order is (4 - 2) / 2 = 1.
- Magnetic nature:
Diamagnetic substances have all their electrons paired up, while paramagnetic substances have unpaired electrons.
Since the bond order is 1, this indicates that there are unpaired electrons in the molecule. Therefore, the diatomic molecule B2 is paramagnetic.
- Conclusion:
The correct answer is option A: The bond order of B2 is 1, and it is paramagnetic.
The atomic number of boron is 5, so the electronic configuration of a single boron atom is 1s^2 2s^2 2p^1. When two boron atoms combine to form a diatomic molecule, they share their valence electrons to form molecular orbitals.
- Hund's Rule violation:
Hund's Rule states that electrons occupy orbitals of the same energy level singly before pairing up. However, in the case of boron, the 2p orbital is not completely filled in the ground state configuration. This violates Hund's Rule as the electrons should first occupy separate orbitals before pairing up.
- Formation of molecular orbitals:
When two boron atoms combine, they form molecular orbitals by combining their atomic orbitals. The 2s orbitals of each boron atom combine to form two molecular orbitals: one bonding (σ) and one antibonding (σ*). The 2p orbitals also combine to form two molecular orbitals: one bonding (π) and one antibonding (π*).
- Bond order calculation:
The bond order is given by the difference between the number of bonding and antibonding electrons divided by 2. In the case of B2, the molecular orbital diagram can be represented as:
σ2s^2 σ*2s^2 π2p^2 π*2p^0
The number of bonding electrons is 4 (2 from σ2s and 2 from π2p), and the number of antibonding electrons is 2 (from σ*2s). Therefore, the bond order is (4 - 2) / 2 = 1.
- Magnetic nature:
Diamagnetic substances have all their electrons paired up, while paramagnetic substances have unpaired electrons.
Since the bond order is 1, this indicates that there are unpaired electrons in the molecule. Therefore, the diatomic molecule B2 is paramagnetic.
- Conclusion:
The correct answer is option A: The bond order of B2 is 1, and it is paramagnetic.
Free Test
FREE
| Start Free Test |
Community Answer
Assuming that Hund's rule is violated, the bond order and magnetic...
For molecules lighter than O2, the increasing ord er order of energies of molecular orbitals is :
Where, π2py and π2pz are degenerate molecular orbitals, first singly occupied and then pairing starts if Hund’s rule is obeyed. If Hund’s rule is violated in B2, electronic arrangement would be :
No unpaired electron-diamagnetic.
Attention JEE Students!
To make sure you are not studying endlessly, EduRev has designed JEE study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in JEE.
|
Explore Courses for JEE exam
|
|
Similar JEE Doubts
Top Courses for JEEView all
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer?
Question Description
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer?.
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer?.
Solutions for Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? in English & in Hindi are available as part of our courses for JEE.
Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer?, a detailed solution for Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? has been provided alongside types of Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice Assuming that Hund's rule is violated, the bond order and magnetic nature of the diatomic molecule B2 is(2010, Single Option Correct Type)a)1 and diamagneticb)0 and diamagneticc)1 and paramagneticd)0 and paramagneticCorrect answer is option 'A'. Can you explain this answer? tests, examples and also practice JEE tests.
|
|
Explore Courses for JEE exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
|
Signup to see your scores
go up
within 7 days!
within 7 days!
Takes less than 10 seconds to signup