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The depth of the centre of pressure on a vertical rectangular gate ( 4m wide , 3m high) with water up to top surface (a) 1m. (b) 1.5m. (c) 2m (d) 2.5m?
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The depth of the centre of pressure on a vertical rectangular gate ( 4...
Calculation of Depth of Centre of Pressure on a Vertical Rectangular Gate

Given:


  • Width of gate (w) = 4m

  • Height of gate (h) = 3m


Case 1: Water level is at 1m

The depth of the centre of pressure can be calculated using the formula:

Depth of Centre of Pressure = h/2 + I/(h*γ)

where,


  • h = height of gate

  • I = moment of inertia of the gate section about an axis passing through the centroid

  • γ = unit weight of water


For a rectangular section, the moment of inertia can be calculated as:

I = (w*h^3)/12

Substituting the given values, we get:

I = (4*3^3)/12 = 27m^4

Substituting the values in the formula, we get:

Depth of Centre of Pressure = 3/2 + 27/(3*9810) = 1.76m

Case 2: Water level is at 1.5m

Using the same formula as above, we get:

Depth of Centre of Pressure = 3/2 + 27/(4.5*9810) = 1.93m

Case 3: Water level is at 2m

Using the same formula as above, we get:

Depth of Centre of Pressure = 3/2 + 27/(6*9810) = 2.09m

Case 4: Water level is at 2.5m

Using the same formula as above, we get:

Depth of Centre of Pressure = 3/2 + 27/(7.5*9810) = 2.22m

Therefore, the depth of centre of pressure on a vertical rectangular gate varies with the water level and can be calculated using the above formula. As the water level increases, the depth of centre of pressure also increases.
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The depth of the centre of pressure on a vertical rectangular gate ( 4m wide , 3m high) with water up to top surface (a) 1m. (b) 1.5m. (c) 2m (d) 2.5m?
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