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A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5m and 6.0m respectively below the free surface the position of the centre of pressure below the free surface?
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A vertical rectangular plane surface is submerged in water such that i...

Position of Centre of Pressure of a Submerged Vertical Rectangular Plane Surface

The position of the centre of pressure of a submerged vertical rectangular plane surface can be determined using the principle of hydrostatic forces acting on the surface.

Given Data:
- Top surface of the rectangular plane: 1.5m below the free surface
- Bottom surface of the rectangular plane: 6.0m below the free surface

Calculation:
1. First, we need to determine the depth of the centroid of the rectangular plane surface below the free surface. The centroid is located at the midpoint of the top and bottom surfaces.
- Depth of centroid = (1.5m + 6.0m) / 2 = 3.75m below the free surface

2. Next, we need to calculate the depth of the centre of pressure below the free surface. The centre of pressure is located at a distance of 1/3 from the bottom of the surface to the centroid.
- Depth of centre of pressure = (1/3) * (6.0m - 3.75m) = 0.75m below the centroid

3. Therefore, the position of the centre of pressure below the free surface is:
- Depth of centre of pressure below the free surface = 3.75m + 0.75m = 4.5m

Hence, the centre of pressure of the submerged vertical rectangular plane surface is located at a depth of 4.5m below the free surface.
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A vertical rectangular plane surface is submerged in water such that its top and bottom surfaces are 1.5m and 6.0m respectively below the free surface the position of the centre of pressure below the free surface?
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