The depth of the centre of pressure on a vertical rectangular gate ( 4...
Calculation of Depth of Centre of Pressure on a Vertical Rectangular Gate
Given:
- Width of gate (w) = 4m
- Height of gate (h) = 3m
Case 1: Water level is at 1m
The depth of the centre of pressure can be calculated using the formula:
Depth of Centre of Pressure = h/2 + I/(h*γ)where,
- h = height of gate
- I = moment of inertia of the gate section about an axis passing through the centroid
- γ = unit weight of water
For a rectangular section, the moment of inertia can be calculated as:
I = (w*h^3)/12Substituting the given values, we get:
I = (4*3^3)/12 = 27m^4Substituting the values in the formula, we get:
Depth of Centre of Pressure = 3/2 + 27/(3*9810) = 1.76mCase 2: Water level is at 1.5m
Using the same formula as above, we get:
Depth of Centre of Pressure = 3/2 + 27/(4.5*9810) = 1.93mCase 3: Water level is at 2m
Using the same formula as above, we get:
Depth of Centre of Pressure = 3/2 + 27/(6*9810) = 2.09mCase 4: Water level is at 2.5m
Using the same formula as above, we get:
Depth of Centre of Pressure = 3/2 + 27/(7.5*9810) = 2.22mTherefore, the depth of centre of pressure on a vertical rectangular gate varies with the water level and can be calculated using the above formula. As the water level increases, the depth of centre of pressure also increases.